運行我的java應用程序時出現gettine錯誤。我的應用程序捆綁在一個.jar文件中。這意味着xsd文件位於.jar文件中。在jar文件中發現類路徑文件時出錯
錯誤:錯誤的
class path resource [classpath*:myschema.xsd] cannot be opened because it does not exist
來源:
@Value("classpath*:myschema.xsd")
private Resource xsdFile;
public boolean validateXML()() throws IOException {
boolean isValidXMLFile = false;
Source xmlFile = new StreamSource(new File(xmlDataFile));
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = null;
File outXsdFile = new File("autogenpath.xsd");
InputStream is =xsdFile.getInputStream();
OutputStream out=new FileOutputStream(outXsdFile);
IOUtils.copy(is, out);
try {
schema = schemaFactory.newSchema(outXsdFile);
} catch (SAXException e1) {
e1.printStackTrace();
isValidXMLFile = false;
log.debug("Error reading schema " + e1.getMessage());
}
try {
Validator validator = schema.newValidator();
validator.validate(xmlFile);
log.debug(xmlFile.getSystemId() + " is valid");
isValidXMLFile = true;
} catch (SAXParseException e) {
isValidXMLFile = false;
log.debug(xmlFile.getSystemId() + " is NOT valid");
log.debug("Reason\t\t: " + e.getLocalizedMessage());
log.debug("Line Number \t: " + e.getLineNumber());
log.debug("Column Number\t: " + e.getColumnNumber());
log.debug("Public Id\t: " + e.getPublicId());
} catch (SAXException e) {
isValidXMLFile = false;
log.debug(xmlFile.getSystemId() + " is NOT valid");
log.debug("Reason\t: " + e.getLocalizedMessage());
}
finally{
try{
out.close();
}catch(Exception e){
e.printStackTrace();
}
}
return isValidXMLFile;
}
我用的getResourceAsStream()他是爲我工作。謝謝 – mahesh