Symfony 3.2 FOSUserBundle Ajax登錄

在FOSUserBundle中，我想在用戶登錄後，在不加載頁面（AJAX查詢）的情況下將用戶重定向到fos_user_profile_show路由。我堅持在這一點上。論壇中有類似的話題，但已經過時了。Symfony 3.2 FOSUserBundle Ajax登錄

AuthenticationHandler.php

<?php 

namespace AppBundle\Handler; 

use Symfony\Component\HttpFoundation\JsonResponse; 
use Symfony\Component\HttpFoundation\RedirectResponse; 
use Symfony\Component\Routing\RouterInterface; 
use Symfony\Component\HttpFoundation\Session\Session; 
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface; 
use Symfony\Component\Security\Core\Exception\AuthenticationException; 
use Symfony\Component\HttpFoundation\Request; 
use Symfony\Component\Security\Core\Security; 
use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface; 
use Symfony\Component\Security\Http\Authentication\AuthenticationFailureHandlerInterface; 

/** 
* Class AuthenticationHandler 
* @package AppBundle\Handler 
*/ 
class AuthenticationHandler implements AuthenticationSuccessHandlerInterface, AuthenticationFailureHandlerInterface 
{ 
    /** 
    * @var RouterInterface 
    */ 
    private $router; 
    /** 
    * @var Session 
    */ 
    private $session; 


    /** 
    * AuthenticationHandler constructor. 
    * @param RouterInterface $router 
    * @param Session $session 
    */ 
    public function __construct(RouterInterface $router, Session $session) 
    { 
     $this->router = $router; 
     $this->session = $session; 
    } 

    /** 
    * @param Request $request 
    * @param TokenInterface $token 
    * @return JsonResponse|RedirectResponse 
    */ 
    public function onAuthenticationSuccess(Request $request, TokenInterface $token) 
    { 

     if ($request->isXmlHttpRequest()) { 
      return new JsonResponse(array('success' => true)); 
     } 
     else { 
      $url = $this->router->generate('fos_user_profile_show'); 
      return new RedirectResponse($url); 
     } 

    } 

    /** 
    * @param Request $request 
    * @param AuthenticationException $exception 
    * @return JsonResponse|RedirectResponse 
    */ 
    public function onAuthenticationFailure(Request $request, AuthenticationException $exception) 
    { 
     if ($request->isXmlHttpRequest()) { 
      return new JsonResponse(array('success' => false, 'message' => $exception->getMessage())); 
     } else { 
      $request->get('session')->set(Security::AUTHENTICATION_ERROR, $exception); 
      return new RedirectResponse($this->router->generate('fos_user_security_login')); 
     } 
    } 
}

services.yml

app.security.authentication_handler: 
    class: AppBundle\Handler\AuthenticationHandler 
    public: false 
    arguments: 
      - "@router" 
      - "@session"

security.yml

firewalls: 
    main: 
     pattern: ^/ 
     form_login: 
      provider: fos_userbundle 
      csrf_token_generator: security.csrf.token_manager 
      check_path: fos_user_security_check 
      success_handler: app.security.authentication_handler 
      failure_handler: app.security.authentication_handler 
     logout:  true 
     anonymous: true

login_content.html.twig

<script> 
    $(document).ready(function(){ 

     $('#_submit').click(function(e){ 
      e.preventDefault(); 
      $.ajax({ 
       type  : $('form').attr('method'), 
       url   : $('form').attr('action'), 
       data  : $('form').serialize(), 
       success  : function(data, status, object) { 
        if (data.success == false) { 
         console.log(data.message); 
        } else { 
         window.location.href = data.targetUrl; 
        } 
       } 
      }); 

    }); 
</script>

來源

2017-05-09 Garrs

我這樣固定;

$url = $this->router->generate('fos_user_profile_show'); 
return new JsonResponse(array('success' => true));

順便說一句，感謝所有這些代碼。

來源

2017-05-13 22:35:20

Symfony 3.2 FOSUserBundle Ajax登錄

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