我試圖讓一個應用程序從一個在線服務器獲取不同的照片,取決於用戶點擊的標記。我的問題是,例如,如果用戶點擊marker1
,他們會得到marker1
的圖片,但當他們嘗試查看的照片時,我的gridview繼續顯示marker1
的照片(沒有任何更改 - 刪除/添加新照片)。如果用戶以開頭,則相同。Android刪除gridview中的所有項目(刷新gridview)
因此,我不明白我在做什麼錯誤,因爲我將適配器設置爲null gridView1.setAdapter(null);
,然後搜索點擊標記的圖像,然後在gridview中顯示它們。但是,即使將適配器設置爲null,gridview中的圖片也不會消失。
這是我的主要代碼:
public static ArrayList<String> image_urls = new ArrayList<>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_poi_photos);
// Check for double values - clear the gridview. reload the images
//image_urls.clear();
gridView1 = (GridView) findViewById(R.id.gridview);
if (gridView1.getChildCount() != 0 || image_urls != null) {
gridView1.setAdapter(null);
}
if (image_urls.isEmpty())
{
getImages();
}
final ImageAdapter adapter = new ImageAdapter(this);
adapter.notifyDataSetChanged();
gridView1.setAdapter(adapter);
}
// GETTING PHOTOS FROM DATABASE
protected void showList() {
try {
JSONObject jsonObj = new JSONObject(myJSON);
photos = jsonObj.getJSONArray(TAG_RESULTS);
for (int i = 0; i < photos.length(); i++) {
JSONObject c = photos.getJSONObject(i);
String email_user = c.getString(TAG_EMAIL_USER);
String poi_name = c.getString(TAG_POI_NAME);
String photo_url = c.getString(TAG_PHOTO_URL);
if ((poi_name.substring(0, 4)).equals(map.markername) && photo_url!=null) {
// add to the picasso gallery
photo_url="http:/xxxxx/photos/"+photo_url;
image_urls.add(photo_url);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
}
public void getImages() {
class GetDataJSON extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
DefaultHttpClient httpclient = new DefaultHttpClient(new BasicHttpParams());
HttpPost httppost = new HttpPost("http://xxxxx/table_photo_out.php");
// Depends on your web service
httppost.setHeader("Content-type", "application/json");
InputStream inputStream = null;
String result = null;
try {
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
inputStream = entity.getContent();
// json is UTF-8 by default
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
result = sb.toString();
} catch (Exception e) {
// Oops
} finally {
try {
if (inputStream != null) inputStream.close();
} catch (Exception squish) {
}
}
return result;
}
@Override
protected void onPostExecute(String result) {
myJSON = result;
showList();
}
}
GetDataJSON g = new GetDataJSON();
g.execute();
}
任何想法可能是錯誤的,或者有什麼更好的辦法?
你在getImages中設置適配器嗎? – Pavya
@ user3676184不,我只是在getImages()調用 – Diana
後,在onCreate中設置我的適配器,您將獲得列表或數組中的所有圖像。意味着如何迭代所有圖像? – Pavya