1
我正在做一個關於製作紙牌應用程序的方法。現在發生的事情是,我正在嘗試點擊一個按鈕,該按鈕應該可以將牌從卡組轉換爲可以玩卡的狀態。但是,聽衆永遠不會觸發。onClickListener沒有觸發
我放了一個system.out.println語句來測試它是否曾經與偵聽器一起進入代碼塊,但事實並非如此。
public class SolitaireGame extends Activity {
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.game);
buttonSound = MediaPlayer.create(SolitaireGame.this, R.raw.button_click);
//instance variables
theDeck = new Deck();
botCardStacks = new ArrayList<BotCardStack>(7);
aceStacks = new ArrayList<AceCardStack>(4);
playableCards = new CardStack(52);
deckButton = (Button) this.findViewById(R.id.deckButton);
deckButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
buttonSound.start();
dealCardsToPlayableStack();
}
});
按照要求,這裏是我的外接卡,可玩堆棧方法
public void dealCardsToPlayableStack() {
Stack<Card> tempStack = new Stack<Card>();
int i = 0;
Card temp, temp1, temp2, temp3;
if(theDeck.getValueOfNext() == 0) {
while(!playableCards.isEmpty()) {
temp = playableCards.popCard();
temp.setVisible(false);
tempStack.push(temp);
}
while(!tempStack.isEmpty()) {
theDeck.addCard(tempStack.pop());
}
}
else if(theDeck.getValueOfNext() >= 3) {
temp1 = theDeck.popCard();
temp1.setVisible(true);
temp2 = theDeck.popCard();
temp2.setVisible(true);
temp3 = theDeck.popCard();
temp3.setVisible(true);
playableCards.addCard(temp3);
playableCards.addCard(temp2);
playableCards.addCard(temp1);
}
else if(theDeck.getValueOfNext() == 2) {
temp1 = theDeck.popCard();
temp1.setVisible(true);
temp2 = theDeck.popCard();
temp2.setVisible(true);
playableCards.addCard(temp2);
playableCards.addCard(temp1);
}
else if(theDeck.getValueOfNext() == 1) {
temp1 = theDeck.popCard();
temp1.setVisible(true);
playableCards.addCard(temp1);
}
}
對不起,響應超級晚了。決賽和假期之間想出了和我在別處度過我的時間。 – bwoods89