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我試圖將C14N轉換應用於某些生成的XML。看來我不能使用LINQ來檢索節點來執行規範化,所以我必須用DOM去「舊學校」,但我認爲我正在陷入默認命名空間。在C#中使用帶默認命名空間的Xpath進行規範化
這是我的代碼示例。
static void Main(string[] args)
{
XmlDocument xDoc = new XmlDocument();
// Load some test xml
string path = @"..\..\TestFiles\Test_1.xml";
if (File.Exists(path) == true)
{
xDoc.PreserveWhitespace = true;
using (FileStream fs = new FileStream(path, FileMode.Open))
{
xDoc.Load(fs);
}
}
//Instantiate an XmlNamespaceManager object.
System.Xml.XmlNamespaceManager xmlnsManager = new System.Xml.XmlNamespaceManager(xDoc.NameTable);
//Add the namespaces used in books.xml to the XmlNamespaceManager.
xmlnsManager.AddNamespace("", "http://www.myApps.co.uk/");
// Create a list of nodes to have the Canonical treatment
//Execute the XPath query using the SelectNodes method of the XmlDocument.
//Supply the XmlNamespaceManager as the nsmgr parameter.
//The matching nodes will be returned as an XmlNodeList.
XmlNodeList nodeList = xDoc.SelectNodes("/ApplicationsBatch/Applications|/ApplicationsBatch/Applications//*", xmlnsManager);
// Perform the C14N transform on the data
XmlDsigC14NTransform transform = new XmlDsigC14NTransform();
transform.LoadInput(nodeList);
MemoryStream ms = (MemoryStream)transform.GetOutput(typeof(Stream));
File.WriteAllBytes(@"..\..\TestFiles\ModifiedTest_1", ms.ToArray());
}
我的XML:
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<ApplicationsBatch xmlns="http://www.myApps.co.uk/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<MessageHeader>
<MessageID>00000003</MessageID>
<Body>11223344556</Body>
<Timestamp>2011-08-02T09:00:00</Timestamp>
<MessageCheck>?</MessageCheck>
</MessageHeader>
<Applications>
<Application>
<ApplicantDetails>
<Title>MR</Title>
<Forename>HOMER</Forename>
<Middlenames>
<Middlename></Middlename>
</Middlenames>
<PresentSurname>SIMPSON</PresentSurname>
<CurrentAddress>
<Address>
<AddressLine1>ADDRESS LINE1</AddressLine1>
<AddressLine2>ADDRESS LINE2</AddressLine2>
<AddressTown>ADDRESS Town</AddressTown>
<AddressCounty>COUNTY</AddressCounty>
<Postcode>POST CODE</Postcode>
<CountryCode>GB</CountryCode>
</Address>
<ResidentFromGyearMonth>2007-01</ResidentFromGyearMonth>
</CurrentAddress>
</ApplicantDetails>
</Application>
<Application>
<ApplicantDetails>
<Title>MR</Title>
<Forename>BART</Forename>
<Middlenames>
<Middlename></Middlename>
</Middlenames>
<PresentSurname>SIMPSON</PresentSurname>
<CurrentAddress>
<Address>
<AddressLine1>ADDRESS LINE1</AddressLine1>
<AddressLine2>ADDRESS LINE2</AddressLine2>
<AddressTown>ADDRESS Town</AddressTown>
<AddressCounty>COUNTY</AddressCounty>
<Postcode>POST CODE</Postcode>
<CountryCode>GB</CountryCode>
</Address>
<ResidentFromGyearMonth>2007-01</ResidentFromGyearMonth>
</CurrentAddress>
</ApplicantDetails>
</Application>
</Applications>
</ApplicationsBatch>
我讀過周圍地區的其他幾個主題和跨越這個Gem來了,但它不是解決了這個問題。
使用XPath Visualiser顯示應選擇所需的節點,但我的代碼未能選擇任何節點。
你的意思是說你不能指定默認的名稱空間用於xpath。這很有意義,因爲xpath將覆蓋具有多個前綴的多個節點,更重要的是必須處理具有空名稱空間的節點,這看起來像xpath中的默認名稱空間。在XML中,您可以使用上下文來幫助確定它是默認名稱空間還是空名稱空間。 –