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我爲sharepoint編寫Android客戶端並使用ksoap2-android-assembly-2.5.8 lib。我已經下一個代碼:ksoap lib的SOAP信封
public class AndroidWSDLKActivity extends Activity {
private static final String NAMESPACE = "http://schemas.microsoft.com/sharepoint/soap/";
private static final String URL = "http://192.168.0.193:30004/SPMobApp/_vti_bin/lists.asmx";
private static final String SOAP_ACTION = "http://schemas.microsoft.com/sharepoint/soap/GetList";
private static final String METHOD_NAME = "GetList";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView lblResult = (TextView) findViewById(R.id.result);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
// Set all input params
request.addProperty("listName", "Tasks");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
// Enable the below property if consuming .Net service
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try
{
List<HeaderProperty> headerList = new ArrayList<HeaderProperty>();
String authentication = android.util.Base64.encodeToString("LOGIN:PASS".getBytes(), android.util.Base64.NO_WRAP);
headerList.add(new HeaderProperty("Authorization", "Basic " + authentication));
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapObject response = (SoapObject)envelope.getResponse();
lblResult.setText(response.getProperty(0).toString());
}
catch(Exception e)
{
lblResult.setText(e.getStackTrace().toString());
}
在此步驟
在調試模式SoapObject響應=(SoapObject)envelope.getResponse();
我有2個錯誤
語法錯誤,插入 「AssignmentOperator表達」 完成 分配
語法錯誤,插入 「;」完成BlockStatements
什麼錯?幫幫我,PLZ
我想你沒有得到肥皂response.you可以得到響應,JSON字符串 – 2012-02-21 11:40:04
我覺得在一個壞的信封錯誤,但我不知道如何解決它,或者創建сorrect信封 – Gorets 2012-02-21 11:47:35
發表您迴應。 – 2012-02-21 11:55:28