用多個參數發送多部分/表單請求？

我試圖上傳一張圖片到服務器，我從服務器獲取不同的響應，這取決於我發送的實體。用多個參數發送多部分/表單請求？

當我發送

FileBody fb = new FileBody(new File(filePath), "image/jpeg"); 
StringBody contentString = new StringBody(directoryID + ""); 

MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); 
entity.addPart("file", fb); 
entity.addPart("directory_id", contentString); 
postRequest.setEntity(entity); 

HttpResponse response = httpClient.execute(postRequest); 
// Read the response 
String jsonString = EntityUtils.toString(response.getEntity());

我得到的迴應是{"status":"Success","code":"200","message":"File has been uploaded Successfully"}

，如果我以這種方式發送相同的文件

Bitmap bitmapOrg = BitmapFactory.decodeFile(filePath); 
ByteArrayOutputStream bao = new ByteArrayOutputStream(); 
bitmapOrg.compress(Bitmap.CompressFormat.JPEG, 90, bao); 
byte[] data = bao.toByteArray(); 

StringBody contentString = new StringBody(directoryID + ""); 
ByteArrayBody ba = new ByteArrayBody(data, "image/jpeg", "file"); 

MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); 
entity.addPart("file", ba); 
entity.addPart("directory_id", contentString); 

postRequest.setEntity(entity); 
HttpResponse response = httpClient.execute(postRequest); 
// Read the response 
String jsonString = EntityUtils.toString(response.getEntity());

，我現在得到的迴應是{"status":"Failure","code":"501","message":"Invalid File to upload"}

所以我想知道爲什麼兩個響應之間有差異？
我是否以正確的方式發送發佈請求參數？
我必須如何以相同的方式發佈視頻？

下面是引用

public void uploadFile(int directoryID, String filePath) { 
    Bitmap bitmapOrg = BitmapFactory.decodeFile(filePath); 
    ByteArrayOutputStream bao = new ByteArrayOutputStream(); 

    String upload_url = BASE_URL + UPLOAD_FILE; 
    bitmapOrg.compress(Bitmap.CompressFormat.JPEG, 90, bao); 

    byte[] data = bao.toByteArray(); 

    HttpClient httpClient = new DefaultHttpClient(); 
    HttpPost postRequest = new HttpPost(upload_url); 
    MultipartEntity entity = new MultipartEntity(
      HttpMultipartMode.BROWSER_COMPATIBLE); 

    try { 
     // Set Data and Content-type header for the image 
     FileBody fb = new FileBody(new File(filePath), "image/jpeg"); 
     ByteArrayBody ba = new ByteArrayBody(data, "image/jpeg", "file"); 
     StringBody contentString = new StringBody(directoryID + ""); 

     // If i do this 
     entity.addPart("file", fb); 
     // I get a valid response 

     // If i do this 
     entity.addPart("file", ba); 
     // I get an invalid response 

     entity.addPart("directory_id", contentString); 
     postRequest.setEntity(entity); 

     HttpResponse response = httpClient.execute(postRequest); 
     // Read the response 
     String jsonString = EntityUtils.toString(response.getEntity()); 
     Log.e("response after uploading file ", jsonString); 

    } catch (Exception e) { 
     Log.e("Error in uploadFile", e.getMessage()); 
    } 

}

來源

2014-03-26 Sheraz Ahmad Khilji

完整的代碼我可以，所以我發佈這個答案來解決這個問題，因爲它可以幫助其他面臨同樣的問題。

問題是，我上傳圖片文件的服務器僅解析了文件，其中包含擴展名爲的JPEG，PNG，GIF等，它忽略了其餘文件。

我以ByteArrayBody的形式發送的圖像文件有文件名屬性沒有擴展名，因此導致此問題。

ByteArrayBody ba = new ByteArrayBody(data, "image/jpeg", "file"); 
entity.addPart("file", ba);

我

ByteArrayBody ba = new ByteArrayBody(data, "image/jpeg", "file.jpeg"); 
entity.addPart("file", ba);

取代它和它的工作。

來源

2014-03-26 07:05:10

用多個參數發送多部分/表單請求？

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