2010-06-11 106 views
1

我在頁面上有兩個單選按鈕列表和一個checkboxlist。理想情況下,基於複選框選定的值,我想啓用/禁用相應的與jquery函數radibuttonlist。jquery按名稱動態獲取單選按鈕列表

但是一些$(「input [name * =」+ columnName +「]」)總是返回null。它無法通過名字找到單選按鈕?

$(function() { 
     function checkBoxClicked() { 

      var isChecked = $(this).is(":checked"); 
      var columnName = "rblColumn" + $(this).parent().attr("alt"); 

      if (isChecked) { 
       $("input[name*=" + columnName + "]").removeAttr("disabled"); 
      } else { 
       $("input[name*=" + columnName + "]").attr("disabled", "disabled"); 

       $("input[name*=" + columnName + "] input").each(function() { 
        $(this).attr("checked", "") 
       }); 

      } 

     } 

     //intercept any check box click event inside the #list Div 
     $(":checkbox").click(checkBoxClicked); 
    }); 




<asp:Panel ID="TestPanel" runat="server"> 
<asp:CheckBoxList ID = "chkColumn" runat="server" RepeatDirection="Horizontal"> 
    <asp:ListItem id = "Column1" runat="server" Text="Column 1" Value="1" alt="1" class="HeadColumn" /> 
    <asp:ListItem id = "Column2" runat="server" Text="Column 2" Value="2" alt="2" class="HeadColumn"/> 
</asp:CheckBoxList> 

<table> 
    <tr> 
     <td> 
      <asp:RadioButtonList ID = "rblColumn1" runat="server" RepeatDirection="Vertical" disabled="disabled"> 
       <asp:ListItem id="liColumn1p" runat="server" /> 
       <asp:ListItem id="liColumn1n" runat="server" /> 
      </asp:RadioButtonList> 
     </td> 
     <td> 
      <asp:RadioButtonList ID = "rblColumn2" runat="server" RepeatDirection="Vertical" disabled="disabled"> 
       <asp:ListItem id="liColumn2p" runat="server" /> 
       <asp:ListItem id="liColumn2n" runat="server" /> 
      </asp:RadioButtonList> 
     </td> 
    </tr> 
</table> 
</asp:Panel> 

來源:

<div id="TestPanel"> 

<table id="chkColumn" border="0"> 
     <tr> 
      <td><span id="Column1" alt="1" class="HeadColumn"><input id="chkColumn_0" type="checkbox" name="chkColumn$0" /><label for="chkColumn_0">Column 1</label></span></td><td><span id="Column2" alt="2" class="HeadColumn"><input id="chkColumn_1" type="checkbox" name="chkColumn$1" /><label for="chkColumn_1">Column 2</label></span></td> 
     </tr> 
    </table> 

<table> 
    <tr> 
     <td> 
      <table id="rblColumn1" class="myRadioButtonList" disabled="disabled" border="0"> 
     <tr> 
      <td><span id="liColumn1p"><input id="rblColumn1_0" type="radio" name="rblColumn1" value="" /></span></td> 
     </tr><tr> 
      <td><span id="liColumn1n"><input id="rblColumn1_1" type="radio" name="rblColumn1" value="" /></span></td> 
     </tr> 
    </table> 
     </td> 
     <td> 
      <table id="rblColumn2" class="myRadioButtonList" disabled="disabled" border="0"> 
     <tr> 
      <td><span id="liColumn2p"><input id="rblColumn2_0" type="radio" name="rblColumn2" value="" /></span></td> 
     </tr><tr> 
      <td><span id="liColumn2n"><input id="rblColumn2_1" type="radio" name="rblColumn2" value="" /></span></td> 
     </tr> 
    </table> 
     </td> 
    </tr> 
</table> 

</div> 
+1

你能後的標記?很難診斷爲什麼一個選擇器不匹配沒有看到它不匹配:) – 2010-06-11 14:07:25

+0

我們可以看到一些html – 2010-06-11 14:08:26

+1

您需要包括**生成的** HTML。忽略所有的服務器端代碼(ASP.NET,JSF/JSP,不管),它對於JavaScript/jQuery來說是不相關的和不可見的。在網頁瀏覽器中打開該頁面,右鍵單擊並選擇*查看源代碼*。這是JS/jQuery可以看到/訪問的真正的HTML。在這裏複製粘貼它。 – BalusC 2010-06-11 14:15:24

回答

1

我知道了。我將cssclass添加到每個radiobutonlist並通過id找到它:

$(「。myRadioButtonList [id * =」+ columnName +「]」)。removeAttr(「disabled」);

這是現在的工作。謝謝,帕特里克。你提醒我有關id /名稱濫用的情況。

+0

很高興你能工作。代碼中還有一個錯誤。我會發佈一個答案,以便您可以看到它完全格式化。 – user113716 2010-06-11 15:22:19

0

爲我工作(jQuery的):

$('[name*="' + columnName + '"]');