楠結果來自javascript

嗨，這是我的第一篇文章和我第一次嘗試在JavaScript（我進入PHP）。問題是，我得到一個NaN的從我的js的結果是如下（如果我能得到的代碼啄嫁接！）楠結果來自javascript

<script type="text/javascript"> 
    function Running_Total() { 
     alert('firing'); 
     var cost1 = "'.$_SESSION['75gmcost'].'"+""; 
     var cost2 = "'.$_SESSION['100gmcost'].'"+""; 
     var cost3 = "'.$_SESSION['1kgcost'].'";+""; 
     var cost4 = "'.$_SESSION['c75gmcost'].'"+""; 
     var qty1 = "'.$_SESSION['qty75gm'].'"+""; 
     var qty2 = "'.$_SESSION['qty100gm'].'"+""; 
     var qty3 = "'.$_SESSION['qty1kg'].'"+""; 
     var qty4 = "'.$_SESSION['qtyc75gm'].'"+""; 
     var sum = 0; 
     sum += cost1 * qty1; 
     sum += cost2 * qty2; 
     sum += cost3 * qty3; 
     sum += cost4 * qty4; 
     $('#tot_cost').empty(); 
     $('#tot_cost').append(sum); 
    } 
</script>

我試圖總結從表單輸入訂單總數，但不知道足以解決南方問題。我想我的PHP變量必須改變，以適應js，但沒有線索怎麼辦？ ##

來源

2013-03-30 JiminSA

那是你生成的源？因爲它看起來像你沒有實際迴應任何$ _SESSION變量的值，你只是寫字符串$ _SESSION ...嘗試將行改爲 var cost1 ='<？php echo $ _SESSION [ 「75gmcost」]; ？>'; – TommyBs

不，它是我寫的源代碼（深入潛水） - 我會嘗試建議的回顯方法... – JiminSA

謝謝TommyBs！我得到了一個結果 - 0！所以我的新問題是爲什麼我的算術不工作？哼哼...... – JiminSA

嘗試在你的代碼與此替換VAR分配：

var cost1 = {$_SESSION['75gmcost']}; 
var cost2 = {$_SESSION['100gmcost']}; 
var cost3 = {$_SESSION['1kgcost']}; 
var cost4 = {$_SESSION['c75gmcost']}; 
var qty1 = {$_SESSION['qty75gm']}; 
var qty2 = {$_SESSION['qty100gm']}; 
var qty3 = {$_SESSION['qty1kg']}; 
var qty4 = {$_SESSION['qtyc75gm']};

在不是解釋爲一個數字（NAN）在JavaScript中值Concatinating字符串結果。

這裏有一個工作的例子，提醒「4」

<?php 
    session_start(); 
    $_SESSION['75gmcost'] = 1; 
    $_SESSION['100gmcost'] = 1; 
    $_SESSION['1kgcost'] = 1; 
    $_SESSION['c75gmcost'] = 1; 
    $_SESSION['qty75gm'] = 1; 
    $_SESSION['qty100gm'] = 1; 
    $_SESSION['qty1kg'] = 1; 
    $_SESSION['qtyc75gm'] = 1; 

    print <<< HERE 
      <script type="text/javascript"> 
    function Running_Total() { 
      alert('firing'); 
     var cost1 = {$_SESSION['75gmcost']}; 
     var cost2 = {$_SESSION['100gmcost']}; 
     var cost3 = {$_SESSION['1kgcost']}; 
     var cost4 = {$_SESSION['c75gmcost']}; 
     var qty1 = {$_SESSION['qty75gm']}; 
     var qty2 = {$_SESSION['qty100gm']}; 
     var qty3 = {$_SESSION['qty1kg']}; 
     var qty4 = {$_SESSION['qtyc75gm']}; 
     var sum = 0; 
     sum += cost1 * qty1; 
     sum += cost2 * qty2; 
     sum += cost3 * qty3; 
     sum += cost4 * qty4; 
     alert(sum); 
    } 
    Running_Total(); 
    </script> 
    HERE; 
?>

來源

2013-03-30 12:06:34 mkruzil

我很確定那些'{...}'在那裏是無效的。而'$ _SESSION'會被解釋爲JS變量，這可能不存在。 –

@FelixKling括號僅在PHP執行期間被解釋。一旦JS執行，括號將被替換爲實際值。 – mkruzil

從什麼時候PHP做到這一點？你有參考嗎？ –

我通常會做這樣的事情（你可以看到結果這裏：http://jorgecardoso.eu/temp/test.php）：

<html> 
<head> 

<?php 
    // just to test 
session_start(); 
$_SESSION['75gmcost'] = 1; 
$_SESSION['100gmcost'] = 1; 
$_SESSION['1kgcost'] = 1; 
$_SESSION['c75gmcost'] = 1; 
$_SESSION['qty75gm'] = 1; 
$_SESSION['qty100gm'] = 1; 
$_SESSION['qty1kg'] = 1; 
$_SESSION['qtyc75gm'] = 1; 
?> 

<script type="text/javascript"> 
    function Running_Total() { 
     alert('firing'); 
     var cost1 = <?php echo $_SESSION['75gmcost'] ?>; 
     var cost2 = <?php echo $_SESSION['100gmcost'] ?>; 
     var cost3 = <?php echo $_SESSION['1kgcost'] ?>; 
     var cost4 = <?php echo $_SESSION['c75gmcost'] ?>; 
     var qty1 = <?php echo $_SESSION['qty75gm'] ?>; 
     var qty2 = <?php echo $_SESSION['qty100gm'] ?>; 
     var qty3 = <?php echo $_SESSION['qty1kg'] ?>; 
     var qty4 = <?php echo $_SESSION['qtyc75gm'] ?>; 
     var sum = 0; 
     sum += cost1 * qty1; 
     sum += cost2 * qty2; 
     sum += cost3 * qty3; 
     sum += cost4 * qty4; 
     alert(sum); 
//  $('#tot_cost').empty(); 
//  $('#tot_cost').append(sum); 
    } 
</script> 

</head> 
<body> 
<script type="text/javascript"> 
Running_Total(); 
</script> 
</body> 
</html>

來源

2013-03-30 13:03:28

楠結果來自javascript

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