我試圖創建一個圖像上傳表單使用CodeIgniter 1.7.2使用CodeIgniter 1.7.2
然而,當我試圖上傳圖片上傳無效目錄,CI告訴我的上傳目錄是無效的。
要檢查這,我上傳一個文件名爲test.txt
與內容Hello, World!
的uploads
目錄,然後我呼應了它的內容,你瞧,它說你好。除此之外,我可以瀏覽目錄並在瀏覽器中查看它的內容,所以目錄肯定存在並且可以查看。
控制器:
class Pictures extends Site_Controller {
// snip...
public function upload() {
$this->load->helper('form');
$this->_render('Do Upload','pictures/upload',array('msg'=>''));
}
public function do_upload() {
$this->load->helper('form');
$config['upload_path'] = base_url().'uploads/';
// test the directory:
// echo file_get_contents($config['upload_path'].'test.txt');
// should echo "Hello, World!"
$config['allowed_types'] = 'gif|jpg|png';
$config['max_size'] = '2048';
$config['max_width'] = '1024';
$config['max_height'] = '768';
$this->load->library('upload', $config);
if (! $this->upload->do_upload())
{
$data = array('msg' => $this->upload->display_errors());
$this->_render('Do Upload (Errors!)','pictures/upload',$data);
}
else
{
$uploaddata = $this->upload->data();
$this->load->model('pictures_Model','pictures');
$this->pictures->insertUploaded($uploaddata,$this->input->post('name'),$this->input->post('caption'));
$data['msg'] = 'Successful Upload!';
$this->_render('Do Upload (Success!)','pictures/upload',$data);
}
}
//...
}
$this->_render()
僅僅是一個快捷方式功能,它包裝與所述指定的數據與指定的標題的佈局指定的圖。
pictures/upload
觀點:
<h1>Do Upload</h1>
<? if (isset($msg)) echo $msg; ?>
<?= form_open_multipart('pictures/do_upload');?>
<input type="file" name="userfile" />
<input type="text" name="name" />
<input type="text" name="caption" />
<br /><br />
<input type="submit" value="Upload" />
</form>
最後,也可能是不必要的,該模型插入:
public function insertUploaded($data,$name,$caption) {
$row = array();
$row['filename'] = $data['file_name'];
$row['mime'] = $data['file_type'];
$row['size'] = $data['file_size'];
$row['name'] = $name;
$row['caption'] = $caption;
$row['img'] = file_get_contents($data['full_path']);
$this->db->insert('pictures',$row);
}
任何想法,爲什麼我的上傳目錄是無效的?
這是爲啥工作? – 2009-12-11 06:48:41
上傳路徑需要是服務器上的文件路徑,而不是URL。 – bradym 2009-12-18 16:25:03