jQuery的.getJSON（）URL錯誤

這是檢索的JSON數據當我使用(METHOD REDACTED)方法：jQuery的.getJSON（）URL錯誤

[{ 
    "group_option": { 
     "OptionsID": "28", 
     "MenuGroupID": "6", 
     "group_options_name": "Select two (2) sides :", 
     "menu_group_option_information": null, 
     "menu_group_option_min_selected": "0", 
     "menu_group_option_max_selected": "2", 
     "fDateAdded": "2014-01-25 08:29:20", 

     "group_option_items": [{ 
      "item": { 
       "OptionItemID": "69", 
       "menu_item_option_name": "Mexican rice", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "70", 
       "menu_item_option_name": "Refried beans", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "71", 
       "menu_item_option_name": "Poblano rice", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "72", 
       "menu_item_option_name": "Charro beans", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "73", 
       "menu_item_option_name": "Caesar salad", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "74", 
       "menu_item_option_name": "Southwestern mashed potatoes", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "75", 
       "menu_item_option_name": "Roasted corn succotash", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "76", 
       "menu_item_option_name": "Poblano cheese corn grits", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "77", 
       "menu_item_option_name": "French Fries", 
       "menu_item_option_additional_cost": null 
      } 
     }, { 
      "item": { 
       "OptionItemID": "78", 
       "menu_item_option_name": "Fiesta salad", 
       "menu_item_option_additional_cost": null 
      } 
     }] 
    } 
}]

這裏是我的其他相關代碼：

<html> 

<head> 
    <meta charset="utf-8" /> 
    <script src="../JQUERY/jquery-1.11.0.js"></script> 
    <script> 
     function getOptions() { 
      var html = new String(); 

      $.getJSON('<URL HERE>', function (data) { 
       alert("function"); 
       //var data = JSON.parse(data); 
       var h = new String(); 
       for (var i = 0; i < data.length; i++) { 
        h += '<div class="data">'; 

        h += data[i]['group_option'].OptionsID + '<br>'; 
        h += data[i]['group_option'].MenuGroupID + '<br>'; 
        h += data[i]['group_option'].group_options_name + '<br>'; 
        h += data[i]['group_option'].menu_group_option_information + '<br>'; 
        h += data[i]['group_option'].menu_group_option_min_selected + '<br>'; 
        h += data[i]['group_option'].menu_group_option_max_selected + '<br>'; 
        h += data[i]['group_option'].fDateAdded + '<br><br><br>'; 

        for (var iter = 0; iter < data[i]['group_option']['group_option_items'].length; iter++) { 

         h += data[i]['group_option']['group_option_items'][iter]['item'].OptionItemID + '<br>'; 
         h += data[i]['group_option']['group_option_items'][iter]['item'].menu_item_option_name + '<br>'; 
         h += data[i]['group_option']['group_option_items'][iter]['item'].menu_item_option_additional_cost + '<br>'; 
         h += '<br><br><br>'; 
        } 
        h += '</div>'; 
       } 
       alert("h"); 
       alert(h); 
       html = h; 
       alert("html equals "); 
       alert(html); 

      }); 
      alert("returning html"); 
      alert(html); 
      return html; 
     } 
    </script> 
    <script> 
     $(document).ready(function() { 
      var str = ""; 
      str = getOptions(); 
      $('#content').append(str); 
     }); 
    </script> 
</head> 

<body> 
    <div id="content"></div> 
</body>

我用.ajax，我什麼都沒有，現在我試圖使用.getJSON。我仍然無法從網站檢索數據。它似乎從來沒有想過去.getJSON(url, function(data)

我的問題

1.爲什麼不會我的代碼讓我進入我的.getJSON功能？

2.在我的.getJSON函數中，需要更改哪些數據才能訪問我的數據？

來源

2014-04-20 Jonathan

您在控制檯的錯誤，你可能需要使用的console.log（）而不是警報（）以及 – kennypu

IM沒有得到任何錯誤 – Jonathan

檢查jQuery庫的路徑是否正確 – SajithNair

添加失效功能的getJSON方法，看看你得到任何錯誤，有

$.getJSON("", function(){ 
    .... 
}) 
.fail(function(jqxhr, textStatus, error) { 
    var err = textStatus + ", " + error; 
    console.log("Request Failed: " + err); 
})

來源

2014-08-12 22:17:42

jQuery的.getJSON（）URL錯誤

回答

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