可能重複: Why can't my C++ compiler deduce template argument for boost function? Isn't the template argument (the signature) of std::function part of its type? 我有以下幾點: #include <functional>
void Foo(std
我有一個對象的過載函數默認值的問題。 如果我有一個函數簽名如下,默認值只能評估一次或每次? class X
{
public:
f(const RWDate& d=RWDate::now());
}
// when calling f() do I get the current time each time?
X z;
z.f();
// is the def
我有以下功能: public static V AddIfNotPresent<K, V>(this Dictionary<K, V> store, K key) where V : new()
public static V AddIfNotPresent<K, V>(this Dictionary<K, V> store, K key)
首先...是有可能超載的功能以這種方式? 如果超