如何從一個臨時表中插入行到另一個臨時表中

-2

ID LogDate  LogTime   InoutMode  
    1 2017-02-23 19:30:00.0000000 1 
    2 2017-02-23 20:00:00.0000000 0 
    3 2017-02-23 20:30:00.0000000 1 
    4 2017-02-23 21:00:00.0000000 0 
    5 2017-02-23 21:30:00.0000000 1 
    6 2017-02-24 08:00:00.0000000 0

上述結果來自臨時表。現在我想將LogTime插入到另一個臨時表中，如下所示。如何從一個臨時表中插入行到另一個臨時表中

 InOutMode-1 =>InTime 
     InOutMode-0 =>OutTime 

    InTime   OutTime 
    19:30:00.0000000 20:00:00.0000000 
    20:30:00.0000000 21:00:00.0000000 
    21:30:00.0000000 08:00:00.0000000

來源

2017-03-08 michael

它已經回答了檢查http://stackoverflow.com/a/42665218/7012137，其同樣，你就必須在不同的日期柱 – Pream

使用2個cte，一個用於InoutMode與1和其他0，並且還根據Id列或日期和時間列的順序給出行號。然後加入這兩個cte的。

查詢

;with cte as(
    select [rn] = row_number() over(
     order by [Id] -- also order by [LogDate], [LogTime] 
    ), * 
    from #your_temp_table_name 
    where [InoutMode] = 1 
), 
cte2 as(
    select [rn] = row_number() over(
     order by [Id] -- also order by [LogDate], [LogTime] 
    ), * 
    from #your_temp_table_name 
    where [InoutMode] = 0 
) 
select 
    t1.[LogTime] [InTime], 
    t2.[LogTime] [OutTime] 
from cte t1 
left join cte2 t2 
on t1.[rn] = t2.[rn];

如果你想結果集到一個新的臨時表。然後最後一部分可以被修改爲

select 
    t1.[LogTime] [InTime], 
    t2.[LogTime] [OutTime] 
into #your_new_temp_table_name 
from cte t1 
left join cte2 t2 
on t1.[rn] = t2.[rn];

Find demo here

來源

2017-03-08 12:07:32 Wanderer

使用INSERT INTO .. SELECT FROM結構像

insert into #temp2 
select ID, LogDate, 
case when InoutMode = 1 then LogTime end as InTime, 
case when InoutMode = 0 then LogTime end as OutTime, 
InoutMode  
from #temp1

來源

2017-03-08 11:37:34 Rahul

要插入一個表格的行到另一個表，你可以這樣寫SQL查詢：

INSERT INTO anotherTemp (InTime) 
    SELECT LogTime 
    FROM Temp 
    WHERE InoutMode = 1 

INSERT INTO anotherTemp (OutTime) 
    SELECT LogTime 
    FROM Temp 
    WHERE InoutMode = 0

請參閱此鏈接更http://www.dofactory.com/sql/insert-into

來源

2017-03-08 11:39:36

如何從一個臨時表中插入行到另一個臨時表中

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