C++中引用的初始化無效

-1

所以我想編譯所以我可以運行我的第一個函數，看看它是否正常工作，但我不斷收到這些錯誤。請幫忙！我得到的錯誤：C++中引用的初始化無效

「的從類型‘字符’的表達類型的參考‘司&’無效初始化」我也得到「在傳遞的`空隙Create_Corporate_File參數1（司&司&，司&，司&）'」

#include <iostream> 
#include <fstream> 
#include <cstdlib> 
using namespace std; 

const int SIZE = 12; 


struct Division 
{ 
char divName [SIZE]; 
double sales [4]; 
}; 

int main() 
{ 
char Div_E; 
char Div_W; 
char Div_N; 
char Div_S; 

void Describe_Program(); 
void Create_Corporate_File (Division& Div_E, Division& Div_W, Division& Div_N, Division& Div_S); 
//void Display_Corporate_Sales (Div_E, Div_W, Div_N, Div_S); 


Describe_Program(); 
Create_Corporate_File (Div_E, Div_W, Div_N, Div_S); 


system ("PAUSE"); 
return 0; 
} 


void Describe_Program() 
{ 
cout << "This program will prompt you to enter the sales amount\n"; 
    << "for each quarter of the North, South, West and East Division.\n"; 
    << "After you enter the sales amount for each quarter, the program\n"; 
    << "will be able to calculate the total quarterly sales for that"; 
    << "division"; 
    <<endl<endl; 
    return; 
} 

void Create_Corporate_File (Division& Div_E, Division& Div_W, Division& Div_N, Division& Div_S) 
{ 
fstream quarterly_sales; 
quarterly_sales.open ("quarterly_sales.dat" ios::out|ios::binary) 

    For(div = 0, div < 4, div++) 
    { 
      Division temp; 

    if (div == 0) 
        temp = Div_E; 
    else 
      if (div == 1) 
        temp = Div_W; 
      else 
       if (div == 2) 
        temp = Div_N; 
       else 
        temp = Div_S; 

        cout << "Please enter the division: "; 
        cin.getline (temp.divName, SIZE); 

     For(sales = 0, sales < 4, sales++) 
     {   
cout << "Please enter the sales amount for quarter " << sales + 1 <<":\n"; 
cin >> temp.sales [sales]; 
    } 
}

來源

2014-10-30 Rodney Benjamin

將'char Div_E;'改爲'Division Div_E;'等等。 – 2014-10-30 20:59:20

你的代碼中有許多其他的錯誤（btw）。 – Borgleader 2014-10-30 21:05:15

Div_E等等都是char類型的，而Create_Corporate_File（）函數需要輸入分區&作爲參數 - 將類型更改爲該參數。

來源

2014-10-30 21:06:42 krojew

C++中引用的初始化無效

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