我需要通過顯示分數和小數的一列,對準他們,所以小數點或正斜槓字符出現在像這樣同一列的textView
格式化數字的列...有沒有更好的方法來對齊Swift textView中的這一列數字?
x 1/1
1 76.04900
x 193.15686
x 310.26471
4 5/4
x 503.42157
6 579.47057
x 696.57843
x 25/16
9 889.73529
x 1006.84314
11 1082.89214
這在Swift中通過插入適當數量的前導空白字符並使用左對齊與列寬相同的字體來實現。
要計算空格的數量,其餘字符或被除數中的字符將從每個數字中的字符總數中排除。這個簡單的任務涉及減去.count
.index(of:)
,被一個事實,即.index(of:)
返回一個可選Array.Index?
不是Int?
我懷疑有可能達到同樣的結果更簡單的方法,並歡迎雨燕下面的代碼任何改進複雜這可能會讓維持它的人更容易。代碼是從我的項目中提取的,並已在Playground中進行了測試。
注意。 textMessage
是單個字符串。它當前顯示在調試區域中。它最終將顯示在textView
中。
//: Playground
import UIKit
var tuningArray = ["1/1", "76.04900", "193.15686", "310.26471", "5/4", "503.42157", "579.47057", "696.57843", "25/16", "889.73529", "1006.84314", "1082.89214"]
var keyArray = ["x", "1", "x", "x", "4", "x", "6", "x", "x", "9", "x", "11"]
var characterCountArray = [Int]()
var scaleSize = Int()
var textMessage = String()
func formatTextMessage() {
var formattedTextArray = [String](repeating: "", count: scaleSize)
for i in 0..<scaleSize {
let element = tuningArray[i]
countNumericCharactersBeforeDotOrSlash (s: element)
}
let largestStringSize = characterCountArray.reduce(Int.min, { max($0, $1) })
for i in 0..<scaleSize {
let thisStringSize = characterCountArray[i]
let blanks = largestStringSize - thisStringSize
let filler = insertWhiteSpace(count: blanks)
formattedTextArray[i].append("\t" + keyArray[i] + "\t" + filler + tuningArray[i] + "\n")
textMessage += formattedTextArray[i]
}
print(textMessage)
}
func insertWhiteSpace(count: Int) -> String {
var filler = ""
for _ in 0..<count {
filler = filler + " "
}
return filler
}
func countNumericCharactersBeforeDotOrSlash (s: String) {
let fractionalNumber = findFractionalNumber(s: s)
let decimalNumber = findDecimalNumber(s: s)
var thisStringSize = 0
if !fractionalNumber && !decimalNumber {
print("Error: invalid number format")
}
if fractionalNumber == true {
let pitchStringArray = Array(s.characters)
let endIndex = pitchStringArray.count
if let slashIndex = pitchStringArray.index(of: "/") {
let dividendFiller = endIndex - slashIndex
thisStringSize = s.characters.count - dividendFiller
}
} else {
if decimalNumber == true {
let pitchStringArray = Array(s.characters)
let endIndex = pitchStringArray.count
if let dotIndex = pitchStringArray.index(of: ".") {
let remainderFiller = endIndex - dotIndex
thisStringSize = s.characters.count - remainderFiller
}
}
}
characterCountArray.append(thisStringSize)
}
func findDecimalNumber(s: String?) -> Bool {
if (s?.contains(".")) == true {
return true
}
return false
}
func findFractionalNumber(s: String?) -> Bool {
if (s?.contains("/")) == true {
return true
}
return false
}
scaleSize = tuningArray.count
formatTextMessage()
Greg,你想對齊上面的文字嗎?看起來像表格合成? –
是的。與Word或Excel類似,但數字需要在小數或正斜槓列上對齊以符合Scala中使用的比例標準(請參見http://www.huygens-fokker.org/microtonality/scales.html) – Greg
All your十進制數字必須像上圖一樣對齊?即全部「。」。必須符合。 –