什麼是這個錯誤：ORA-00933：SQL命令不能正確地結束

Question

SELECT CU.CUST_CODE 
FROM AR_CUSTOMERS CU 
WHERE CU.CUST_CODE=TM.CUST_CODE 
UNION 
SELECT ITS.ITEMS_CODE 
FROM AR_ITEMS ITS 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT ITS.ITEMS_NAME 
FROM AR_ITEMS ITS 
WHERE TM.INVOICE_NO = TD.INVOICE_NO AND ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT TO_CHAR(TM.JOB_DATE,'MON-YY')MON, TO_CHAR(TM.JOB_DATE,'MM-YY')MM 
FROM AR_TRANS_MASTER TM 
SELECT SUM(TD.QUANTITY)QUANTITY, SUM(TD.PRICE)UNIT 
FROM AR_TRANS_DETAIL TD 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
TM.JOB_DATE :STARTDATE AND :STOPDATE 
GROUP BY 
CU.CUST_CODE,ITS.ITEMS_CODE,ITS.ITEMS_NAME,TO_CHAR(TM.JOB_DATE,'MON-YY'),TO_CHAR(TM.JOB_DATE,'MM-YY') 
ORDER BY 
MM ASC 

讓我知道什麼是錯誤是這樣，任何人都可以解釋或糾正

00000 - 「SQL命令不能正確地結束」
*原因：
*動作：
行錯誤：15列：1

MADE，現在存在的誤差（聯合）的該修正後：

ORA-00904： 「TM」 「CUST_CODE」：無效的標識符 00904. 00000 - 「％S：無效識別符」 * 原因：
*動作： 行錯誤：3欄：22

如何找到這個

Answer 1

它看起來像你錯過了這些線之間的「聯盟」（或任何其他預期運營商）：

FROM AR_TRANS_MASTER TM 
SELECT SUM(TD.QUANTITY)QUANTITY, SUM(TD.PRICE)UNIT 

你可能打算：

SELECT CU.CUST_CODE 
FROM AR_CUSTOMERS CU 
WHERE CU.CUST_CODE=TM.CUST_CODE 
UNION 
SELECT ITS.ITEMS_CODE 
FROM AR_ITEMS ITS 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT ITS.ITEMS_NAME 
FROM AR_ITEMS ITS 
WHERE TM.INVOICE_NO = TD.INVOICE_NO AND ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT TO_CHAR(TM.JOB_DATE,'MON-YY')MON, TO_CHAR(TM.JOB_DATE,'MM-YY')MM 
FROM AR_TRANS_MASTER TM 
UNION 
SELECT SUM(TD.QUANTITY)QUANTITY, SUM(TD.PRICE)UNIT 
FROM AR_TRANS_DETAIL TD 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
TM.JOB_DATE :STARTDATE AND :STOPDATE 
GROUP BY 
CU.CUST_CODE,ITS.ITEMS_CODE,ITS.ITEMS_NAME,TO_CHAR(TM.JOB_DATE,'MON-YY'),TO_CHAR(TM.JOB_DATE,'MM-YY') 
ORDER BY 
MM ASC 

Answer 2

也許，第15行缺少UNION。

SELECT CU.CUST_CODE 
FROM AR_CUSTOMERS CU 
WHERE CU.CUST_CODE=TM.CUST_CODE 
UNION 
SELECT ITS.ITEMS_CODE 
FROM AR_ITEMS ITS 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT ITS.ITEMS_NAME 
FROM AR_ITEMS ITS 
WHERE TM.INVOICE_NO = TD.INVOICE_NO AND ITS.ITEMS_CODE = TD.ITEM_CODE 
UNION 
SELECT TO_CHAR(TM.JOB_DATE,'MON-YY')MON, TO_CHAR(TM.JOB_DATE,'MM-YY')MM 
FROM AR_TRANS_MASTER TM 
UNION 
SELECT SUM(TD.QUANTITY)QUANTITY, SUM(TD.PRICE)UNIT 
FROM AR_TRANS_DETAIL TD 
WHERE ITS.ITEMS_CODE = TD.ITEM_CODE 
TM.JOB_DATE :STARTDATE AND :STOPDATE 
GROUP BY 
CU.CUST_CODE,ITS.ITEMS_CODE,ITS.ITEMS_NAME,TO_CHAR(TM.JOB_DATE,'MON- YY'),TO_CHAR(TM.JOB_DATE,'MM-YY') 
ORDER BY 
MM ASC 

Answer 3

我想你在工會的情況下，你不能在一個查詢中使用引用名稱。
實施例

select a.col1 from tab1 a where a.col1=b.col2 
    union 
    select b.col2 from tab2 b; 

b爲一個表的查詢2參考，我認爲它不能在查詢1可以使用請不要檢查