如何停止循環以輸入輸入？

Question

我從來沒有遇到過這個問題，這意味着我甚至不知道何時或如何研究這個話題。我正試圖創造一個幸運計劃的輪子，但投入卻表現得很奇怪。基本上，我有一個if循環，當我輸入數字1來猜測密碼短語的一個字母時，它會停下來讓我輸入輸入，但是當我輸入2來猜測整個短語時，將繼續並再次循環。這裏是代碼：

import java.util.Random; 
import java.util.Scanner; 


public class WheelOfFortune { 

/** 
* B. Stephens 
* CSC-151 
* This program is designed to immerse you in the experience of the television game show. 
* Have fun! 
*/ 

public static void main(String[] args) { 

    // declare an array and allocate memory for 26 letters 
    String letterBoard1 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; 
    String letterBoard2 = "abcdefghijklmnopqrstuvwxyz"; 

    if(letterBoard1.equalsIgnoreCase(letterBoard2)){ 

     System.out.println("Welcome to the Wheel of Fortune"); 

     // declare and initialize random number values 
     int [] moneyAmount = {100, 300, 500, 700, 900 , 2000, 3000, 5000, -1000, 0}; 

     String secretPhrase = "show me the money"; 
     String guesses = " "; // the user's guesses 
     Scanner input = new Scanner (System.in); 
     int turn = 1; 
     int player1 = 1; 
     int player2 = 2; 
     int player3 = 3; 
     int player1Bank = 0; 
     int player2Bank = 0; 
     int player3Bank = 0; 

     boolean notDone = true; 
     while (true) { 
       // display available letters 
       System.out.print("\nAvailable letters - " + letterBoard1 + "\n"); 

       System.out.println("\nHere is the puzzle:"); 

       // print out the board 
       notDone = false; 
       for (char secretLetter : secretPhrase.toCharArray()){ // iterates over the letters 
        if (guesses.indexOf(secretLetter) == -1) { // not one of the guesses 
         System.out.print('*'); 
         notDone = true; 
        } else { 
         System.out.print(secretLetter); 
        } 
       } 
       if (! notDone) {break;} 

       // get user's guess 
       System.out.print("\n\nWould you like to Spin (1) or Guess (2) the puzzle? "); 
       int choiceNumber = input.nextInt(); 
       if (choiceNumber == 1){ 
        Random random = new Random(); 
        System.out.println("\nYou landed on $" + moneyAmount[random.nextInt(moneyAmount.length)]); 
        if (moneyAmount[random.nextInt(moneyAmount.length)] == 0) { 
         System.out.println("You lose your turn"); 
        } 
        if (moneyAmount[random.nextInt(moneyAmount.length)] == 1000){ 
         System.out.println("You lose your turn and $1000"); 
         if (turn == player1){ 
          player1Bank = player1Bank - 1000; 
         } 
         if (turn == player2){ 
          player2Bank = player2Bank - 1000; 
         } 
         if (turn == player3){ 
          player3Bank = player3Bank - 1000; 
         } 
        } 
        if (moneyAmount[random.nextInt(moneyAmount.length)] != 0 & moneyAmount[random.nextInt(moneyAmount.length)] != -1000) { 
         System.out.print("Select your letter from the available list above: "); 
         String letterGuess = input.nextLine(); 
         letterBoard1 = letterBoard1.replace(letterGuess , ""); 
         String letter = input.next(); 
         guesses += letter; 
        } 
       } 
       if (choiceNumber == 2){ 
        System.out.print("Guess the puzzle: "); 
        String puzzleGuess = input.nextLine(); 
        if (puzzleGuess == secretPhrase) { 
         System.out.println("Congratulations! You guessed the puzzle!"); 
        } 
       } 
       if (choiceNumber != 1 & choiceNumber !=2) { 
        System.out.println("The number you input is not a choice\n"); 
       } 
      } // end while (true) 

      System.out.println("\nCongratulations!"); 

     } // end ignore case 

    } // end main 

} // end class 

對不起，冗長的代碼，但它是一個詳細的程序，需要大量的編碼。我還沒有完成，所以我仍然會做更多的工作。

的是給我找麻煩代碼段是：

if (choiceNumber == 2){ 
    System.out.print("Guess the puzzle: "); 
    String puzzleGuess = input.nextLine(); 
    if (puzzleGuess == secretPhrase) { 
     System.out.println("Congratulations! You guessed the puzzle!") 
    } 
} 

我將在數字「2」進入，以猜詞，但它是所有循環再繞。這裏是控制檯輸出的樣子：

Welcome to the Wheel of Fortune 

Available letters - ABCDEFGHIJKLMNOPQRSTUVWXYZ 

Here is the puzzle: 
_ _ _ _ _ _ _ _ _ _ _ _ _ _ 

Would you like to Spin (1) or Guess (2) the puzzle? 2 
Guess the puzzle: 
Available letters - ABCDEFGHIJKLMNOPQRSTUVWXYZ 

Here is the puzzle: 
_ _ _ _ _ _ _ _ _ _ _ _ _ _ 

Would you like to Spin (1) or Guess (2) the puzzle? 

出於某種原因，破折號的間距有點搞砸了，但你的想法。

我想讓代碼做的只是讓我嘗試並輸入祕密短語。

Answer 1

一個常見問題。當您調用nextInt（）時，掃描器不會從流中使用換行符，因此只要您調用nextLine（），就會立即將剩下的換行符作爲輸入，就像您輸入「」一樣。當讀取輸入最好是在一個字符串來讀取，然後解析出你所需要的，如下面的Integer.parseInt（String s）將任何數字

// get user's guess 
     System.out.print("\n\nWould you like to Spin (1) or Guess (2) the puzzle? "); 
     int choiceNumber = Integer.parseInt(input.nextLine()); 

編輯： 你有另一處代碼下，你正在捕獲一個額外的輸入：

if (spinMoney != 0 && spinMoney != -1000) { 
    System.out.print("Select your letter from the available list above: "); 
    String letterGuess = input.nextLine(); 
    letterBoard1 = letterBoard1.replace(letterGuess, ""); 
    // String letter = input.next(); // get rid of this! 
    guesses += letterGuess; // use the guess captured above to append 
    // also consider using StringBuilder here instead 

還有很多代碼中的錯誤，包括你展示字符板和密碼（在全部大寫字母板比賽之間的大/小寫問題會永遠不要與你的祕密短語匹配，嘗試使用一些toUpperCase（）和toLowerCase（）），反覆調用random.nextInt（一個值符號邏輯） ror等等，但是你可以慢慢地解決它們。乾杯!

int spinMoney = moneyAmount[random.nextInt(moneyAmount.length)]; 
     // determine random money once 
     System.out.println("\nYou landed on $" + spinMoney); 
     if (spinMoney == 0) { 
     System.out.println("You lose your turn"); 
     } 
     if (spinMoney == -1000){ // changed to -1000 for logic error 
     System.out.println("You lose your turn and $1000"); 

Answer 2

你必須將它設置爲false，你，你已經解決了這個難題 因爲周圍的真/假布爾值，你的循環工作停止最後一條語句中。

notDone = false; 

其實你有2個錯誤

boolean notDone = true; 
    while (true) { 
    } 

這個循環將永遠不會結束，你想添加

while(notDone) 

所以首先設置

notDone = false; 
while(notDone == false) 

，並在最後的IF聲明

notDone = true;