2016-08-25 47 views
1

我想在java代碼中獲取一個文件作爲流。該URI正在返回一個PDF文件。下面是我的代碼片段:從JAX-RS流式傳輸pdf文件響應:'401:Unauthorized'for url

public void downloadToLocal() { 

    try{ 
     Authenticator.setDefault(new Authenticator() { 
      @Override 
      protected PasswordAuthentication getPasswordAuthentication() { 
       return new PasswordAuthentication("test", 
         "test".toCharArray()); 
      } 
     }); 
     URL url = new URL("http://***"); 

     /*String encodedAuthorizedUser = new String(com.sun.jersey.core.util.Base64.encode("***" + ":" + "***")); 
     HttpURLConnection httpCon = (HttpURLConnection) url.openConnection(); 
     httpCon.setRequestProperty("Authorization", "Basic " + encodedAuthorizedUser);*/ 

     InputStream is = url.openStream(); 
     FileOutputStream fos = new FileOutputStream("C:\\db\\test.pdf"); 

     byte[] buffer = new byte[1024]; 
     int noOfBytes = 0; 

     while ((noOfBytes = is.read(buffer)) != -1) { 
      fos.write(buffer, 0, noOfBytes); 
     } 

     fos.close(); 
     is.close(); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 

} 

下面是我收到的例外:

java.io.FileNotFoundException: Response: '401: Unauthorized' for url: '*********' 
    at weblogic.net.http.HttpURLConnection.getInputStream(HttpURLConnection.java:487) 
    at weblogic.net.http.SOAPHttpURLConnection.getInputStream(SOAPHttpURLConnection.java:37) 
    at java.net.URL.openStream(URL.java:1010) 
    at com.bt.ngwfmt.framework.services.dlite.DliteServiceClient.downloadToLocal(DliteServiceClient.java:882) 
    at com.bt.ngwfmt.framework.rest.DliteRestHandler.persistDCV(DliteRestHandler.java:167) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    at java.lang.reflect.Method.invoke(Method.java:597) 
    at com.sun.jersey.spi.container.JavaMethodInvokerFactory$1.invoke(JavaMethodInvokerFactory.java:60) 
    at com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$TypeOutInvoker._dispatch(AbstractResourceMethodDispatchProvider.java:185) 
    at com.sun.jersey.server.impl.model.method.dispatch.ResourceJavaMethodDispatcher.dispatch(ResourceJavaMethodDispatcher.java:75) 
    at com.sun.jersey.server.impl.uri.rules.HttpMethodRule.accept(HttpMethodRule.java:302) 
    at com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147) 
    at com.sun.jersey.server.impl.uri.rules.ResourceClassRule.accept(ResourceClassRule.java:108) 
    at com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147) 
    at com.sun.jersey.server.impl.uri.rules.RootResourceClassesRule.accept(RootResourceClassesRule.java:84) 
    at com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1542) 
    at com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1473) 
    at com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1419) 
    at com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1409) 
    at com.sun.jersey.spi.container.servlet.WebComponent.service(WebComponent.java:409) 
    at com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:558) 
    at com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:733) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) 
    at weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227) 
    at weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125) 
    at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:300) 
    at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:183) 
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.wrapRun(WebAppServletContext.java:3717) 
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3681) 
    at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321) 
    at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120) 
    at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2277) 
    at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2183) 
    at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1454) 
    at weblogic.work.ExecuteThread.execute(ExecuteThread.java:209) 
    at weblogic.work.ExecuteThread.run(ExecuteThread.java:178) 

here我以參考。我從那裏嘗試了兩種方法。我也發現了類似問題here。但無法得到我需要做的跳過這個密碼認證。當我在瀏覽器中打開url並手動提供用戶名和密碼時,這是工作。

任何幫助將不勝感激。 :)

注意:我正在使用weblogic 10.3.5。由於

+0

您還沒有一個正確的方式使用身份驗證。檢查這個http://stackoverflow.com/questions/496651/connecting-to-remote-url-which-requires-authentication-using-java –

+0

這種身份驗證的方式通常是正確的。這個問題在WebLogic中。 –

回答

2

它看起來像WebLogic特定問題與默認的身份驗證
嘗試顯式設置AUTH頭:

URLConnection conn = url.openConnection(); 
String creds = user + ":" + pass; 
String encodedCreds = "Basic " + new String(new Base64().encode(creds.getBytes())); 
conn.setRequestProperty ("Authorization", encodedCreds); 
InputStream in = conn.getInputStream(); 
+0

另一種方法是使用自定義處理程序,因爲它在這裏提出 - https://community.oracle.com/thread/1668714?start=0 –

+0

如果您的用戶名和密碼不包含s [特殊符號,您可以指定只是在URL - http:// user:[email protected]/url 或者使用第三方http客戶端,例如apache –

+0

嗨,謝謝。它的工作:)乾杯 –