java中的數字金字塔。

Question

我需要用java打印出一個數字金字塔。它的數量是2的倍數以及下面的數據。但我有它的代碼只能帶出1的倍數沒有空格。

     1 
        1 2 1 
       1 2 4 2 1 
      1 2 4 8 4 2 1 
     1 2 4 8 16 8 4 2 1 
    1 2 4 8 16 32 16 8 4 2 1 
1 2 4 8 16 32 64 32 16 8 4 2 1 

這是我的代碼。

import java.util.Scanner; 

public class NumericPyramid { 

    public static void main(String[] args) { 

     Scanner sc = new Scanner(System.in); 

     //Taking noOfRows value from the user 

     System.out.println("How Many Rows You Want In Your Pyramid?"); 

     int noOfRows = sc.nextInt(); 

     //Initializing rowCount with 1 

     int rowCount = 1; 

     System.out.println("Here Is Your Pyramid"); 

     //Implementing the logic 

     for (int i = noOfRows; i > 0; i--) { 
      //Printing i*2 spaces at the beginning of each row 

      for (int j = 1; j <= i*2; j++) { 
       System.out.print(" "); 
      } 

      //Printing j value where j value will be from 1 to rowCount 

      for (int j = 1; j <= rowCount; j++) { 
       System.out.print(j+" "); 
      } 

      //Printing j value where j value will be from rowCount-1 to 1 

      for (int j = rowCount-1; j >= 1; j--) {     
       System.out.print(j+" ");    
      }       

      System.out.println(); 

      //Incrementing the rowCount 

      rowCount++; 
     } 
    } 
} 

輸出：

How Many Rows You Want In Your Pyramid? 

7 

Here Is Your Pyramid 

       1 

      1 2 1 

      1 2 3 2 1 

     1 2 3 4 3 2 1 

     1 2 3 4 5 4 3 2 1 

    1 2 3 4 5 6 5 4 3 2 1 

    1 2 3 4 5 6 7 6 5 4 3 2 1 

Answer 1

對於從1每個JC你需要寫2道^ Jñ。目前，你只寫j。 所以寫函數給定k返回2^k。

編輯：對於更大的n您需要使用的BigInteger：

import java.math.BigInteger; 

public class NumericPyramid { 
    private static BigInteger pow(int exponent) { 
     BigInteger result = new BigInteger("1"); 
     BigInteger two = new BigInteger("2"); 
     for (int i = 0; i < exponent; i++) { 
      result = result.multiply(two); 
     } 
     return result; 
    } 

，並用它在這兩個for循環。替換

System.out.print(j+" "); 

與

System.out.print(pow(j)+" "); 

Answer 2

金字塔變爲1 2 4 8 16，這是1×2 = 2的序列，2 * 2 = 4，4 * 2 = 8等等，然後反轉，8/2 = 4,4/2 = 2,2/2 = 1，當中心點只需要乘以2併除以2

for (int i = 0; i < noOfRows; i++) { 
      int cont = 1; 
      for (int j = 0; j <= i; j++) { 
       System.out.print(cont + " "); 
       cont = cont * 2; 
      } 
      cont = cont/2; 
      for (int j = 0; j < i; j++) { 
       cont = cont/2; 
       System.out.print(cont + " "); 
      } 
      System.out.println(); 
     }