2013-08-22 33 views
3

我有一個動態模塊,它會在我的應用程序運行時將類型添加到它。該模塊通過以下代碼創建:動態模塊何時可以有類型加載異常?

var assemblyName = new AssemblyName("MyAssembly"); 
var assemblyBuilder = AppDomain.CurrentDomain.DefineDynamicAssembly(assemblyName, AssemblyBuilderAccess.Run); 
MyClass.RuntimeBoundDerivedTypesModule = assemblyBuilder.DefineDynamicModule("MainModule"); 

應用程序的其他部分有時也會在模塊的程序集上調用GetTypes()。偶爾,當發生這種情況時,我會爲動態模塊中的某個類型獲取TypeLoadException。棧跟蹤是:

at System.Reflection.RuntimeModule.GetTypes(RuntimeModule module) 
    at System.Reflection.RuntimeModule.GetTypes() 
    at System.Reflection.Assembly.GetTypes() 

我的問題是:什麼可能會導致此異常?運行時模塊是否真的是線程安全的,或者當類型通過創建被中途調用時,GetTypes()被調用時會有競爭條件嗎?

編輯:這裏有一小段代碼可以爲我可靠地重現錯誤。現在看來,如果GetTypes()被調用DefineType()和CreateType(之間)出現異常:

var assemblyName = new AssemblyName("MyAssembly"); 
var assemblyBuilder = AppDomain.CurrentDomain.DefineDynamicAssembly(assemblyName, AssemblyBuilderAccess.Run); 
ModuleBuilder m = assemblyBuilder.DefineDynamicModule("foo"); 

Action doStuff =() => { 
    try { 
     if (!m.GetTypes().Any() || Guid.NewGuid().GetHashCode() % 2 == 0) { 
      var t = m.DefineType(
       "MyType" + Guid.NewGuid().ToString().Replace("-", ""), 
       TypeAttributes.Public | TypeAttributes.Class | TypeAttributes.AutoClass | TypeAttributes.AnsiClass | TypeAttributes.BeforeFieldInit | TypeAttributes.AutoLayout, 
       typeof(object) 
      ); 
      Thread.Sleep(1); 
      t.CreateType(); 
     } 
     else { 
      //m.GetTypes(); // interestingly, this always works 
      assemblyBuilder.GetTypes(); 
      "it worked!".Dump(); 
     } 

    } catch (Exception ex) { 
     Console.WriteLine(ex); 
    } 
}; 

// in synchronous mode, I only see failures if I leave out the call to CreateType(). In that 
// case, it never works 
//Enumerable.Range(1, 1000) 
// .ToList() 
// .ForEach(_ => doStuff()); 

// in the async mode, I always see failures with Thread.Sleep() and sometimes 
// see them if I take the sleep out. I often see a mix of failures and "It worked!" 
var threads = Enumerable.Range(1, 100).Select(t => new Thread(() => doStuff())) 
    .ToList(); 
threads.ForEach(t => t.Start()); 
threads.ForEach(t => t.Join()); 

回答