使用SELECT DISTINCT COUNT獲取數據庫中的錯誤金額

Question

我正在跟蹤賣家在亞馬遜上銷售的產品價格是否低於某個特定價格。我在數據庫中存儲產品，銷售商和違規行爲。我試圖顯示在24小時內違規的賣家人數。我沒有顯示違規賣家的數量，而是收到違規總數。

ViolationsRepository.php

public function countNumberOfSellersInViolationsForVendorInLast24Hours($vendorId) 
{ 
    $select = "SELECT DISTINCT COUNT(
     CASE 
     WHEN v.source = 'amazon' THEN 
      (SELECT DISTINCT s.id 
      FROM seller_info_amazon AS sai 
      LEFT JOIN sellers_amazon AS sa ON sa.amazon_id = sai.id 
      LEFT JOIN sellers AS s ON sa.seller_id = s.id 
      WHERE sai.unique_id = v.seller_id_amazon AND s.id IS NOT NULL 
      LIMIT 1) 
     WHEN v.source = 'ebay' THEN 
      (SELECT s.id 
      FROM sellers AS s 
      WHERE s.id = v.seller_id_ebay 
      LIMIT 1) 
     WHEN v.source = 'google' THEN 
      (SELECT s.id 
      FROM sellers AS s 
      WHERE s.id = v.seller_id_google 
      LIMIT 1) 
     END) 
    FROM 
     violations AS v 

    "; 

    $timeLimit = new \DateTime('24 hours ago'); 

    $where = " WHERE v.vendor_id = :vendorId AND v.last_scout_date >= :timeLimit \n"; 


    $query = $this->getEntityManager()->getConnection()->prepare($select . $where); 
    $query->bindValue(':vendorId', $vendorId); 
    $query->bindValue(':timeLimit', $timeLimit->format("Y-m-d h:i:s")); 

    $query->execute(); 

    return $query->fetchColumn(); 

} 

sellers_amazon TABLE

seller_id amazon_id 

侵犯TABLE

id  vendor_id seller_id_amazon last_scout_date source 

seller_info_amazonŤ ABLE

id unique_id name 

賣家表

id originating_vendor_id name 

Answer 1

解決了這個 - 的SELECT COUNT(DISTINCT ...代替SELECT DISTINCT COUNT(...。