Corona SDK將store.purchase（）總是在所有情況下超時/返回？

Question

將store.purchase在所有情況下（）總是超時/回報？

這是我可以確信，我可以離開我的模態對話框，在原地等待來自該回調響應的微調？

（並沒有真正說在http://docs.coronalabs.com/daily/api/library/store/purchase.html#store.purchase在docs這事）

Answer 1

是的，它的作用。當您使用store.init([storeName,] listener)啓動店裏指定的商店名稱和網上交易方式，即store.init("apple", transactionCallback)一個回調函數。在這個回調函數中，你可以檢查某些事務狀態。

local function transactionCallback(event) 
    local transaction = event.transaction 
    print("EVENT:PHASE = " .. transaction.state) 

    if transaction.state == "purchased" then 
     print("Transaction succuessful!") 
     print("productIdentifier", transaction.productIdentifier) 
     print("receipt", transaction.receipt) 
     print("signature", transaction.signature) 
     print("transactionIdentifier", transaction.identifier) 
     print("date", transaction.date) 
    elseif transaction.state == "restored" then 
     print("Transaction restored (from previous session)") 
     print("signature", transaction.signature)   
     print("productIdentifier", transaction.productIdentifier) 
     print("receipt", transaction.receipt) 
     print("transactionIdentifier", transaction.identifier) 
     print("date", transaction.date) 
     print("originalReceipt", transaction.originalReceipt) 
     print("originalTransactionIdentifier", transaction.originalIdentifier) 
     print("originalDate", transaction.originalDate) 
    elseif transaction.state == "cancelled" then 
     print("User cancelled transaction") 
    elseif transaction.state == "failed" then 
     print("Transaction failed, type:", transaction.errorType, transaction.errorString) 
    else 
     print("unknown event") 
    end 
end 

Answer 2

是的，但如果它感知某種互聯網連接的（哪怕是個壞），直到它接收響應，並考慮到玩家在玩移動互聯網上經常可以連接差會保持對話了。如果在合理的時間內沒有收到響應，您可能需要插入Corona計時器來取消進程並通過對話框通知用戶。