數據不保存在MySQL使用PHP

Question

我有php頁面輸入審計的一些細節，最後保存在database.But當我輸入的數據，並按保存按鈕。但它不會保存在數據庫中。當我使用error_log（）函數來檢查php函數是否正在工作或不在下面時，在我的日誌文件中只有「已啓動」的地方..他們沒有「提交」和進一步的數據庫錯誤信息。

注：即時通訊新的PHP，開始開發PHP應用程序中使用XAMPP和記事本+

auditentry.php

<?php 
    include("config.php"); 
    include("header.php"); 
    session_start(); 
    error_log("started"); 
    ?> 

<link href="<?=BASE_URL?>bootstrap/css/bootstrap.css" rel="stylesheet"> 
<link rel="stylesheet" href="<?=BASE_URL?>/bootstrap/css/bootstrap.min.css"> 
<script type="text/javascript" src="<?=BASE_URL?>js/jquery.js"></script> 
<script src="<?=BASE_URL?>bootstrap/js/bootstrap.js"></script> 
<link href="<?=BASE_URL?>bootstrap/css/bootstrap-responsive.css" rel="stylesheet"> 

<div class="col-md-10 main">  

<h1 class="page-header"> 
    Audit Plan Entry   
</h1>  
    <form class="form-horizontal" role="form"> 
    <div class="form-group"> 
     <label class="control-label col-sm-2" for="usr">Audit ID:</label> 
     <div class="col-sm-5"> 
      <input type="text" class="form-control" id="auditid" name ="auditid" placeholder="Eg: IA01"> 
     </div> 
    </div> 
    <div class="form-group"> 
     <label class="control-label col-sm-2" for="pwd">Year:</label> 
     <div class="col-sm-5"> 
      <input type="text" class="form-control col-xs-3" id="year" name ="year"> 
     </div> 
    </div> 
    <div class="form-group"> 
     <label class="control-label col-sm-2" for="usr">Month:</label> 
     <div class="col-sm-5"> 
      <input type="text" class="form-control" id="month" name ="month"> 
     </div> 
    </div> 
    <div class="form-group"> 
     <label class="control-label col-sm-2 " for="sel1">Status:</label> 
     <div class="col-sm-5"> 
      <select class="form-control" id="sel1" name="status"> 
      <option>Planned</option> 
      <option>Scheduled</option> 
      <option>Completed</option> 
      <option>Cancelled</option> 
      </select> 
     </div> 
    </div> 

    <div class="form-group"> 
     <label class="control-label col-sm-2" for="comment">Comment:</label> 
     <div class="col-sm-5"> 
      <textarea class="form-control" rows="3" id="comment" name="comment"></textarea> 
     </div> 
    </div> 

    <div class="form-group">   
      <div class=" col-sm-offset-3"> 
      <button type="submit" name="submit" id ="submit" class="btn btn-primary">Save</button> 
      <button type="reset" name="submit1" id ="clear" class="btn btn-primary">Cancel</button> 
      </div> 

    </div>  
    </form>   
    </div> 

    <?php 
     if(isset($_POST['submit'])) 
      { 
     error_log("Submitted"); 
        if(trim($_POST['auditid'])=='') 
         { 
       echo "<script language='javascript'>alert('Please Enter Audit ID.');</script>"; 
       exit; 
         }     
       elseif(trim($_POST['year'])=='') 
         { 
       echo "<script language='javascript'>alert('Please Enter Year.');</script>"; 
       exit; 
         } 
       elseif(trim($_POST['month'])=='') 
         { 
       echo "<script language='javascript'>alert('Please Enter Month.');</script>"; 
       exit; 
         } 
       elseif(trim($_POST['Status'])=='None') 
         { 
       echo "<script language='javascript'>alert('Please Enter Status.');</script>"; 
       exit; 
         } 
       $audit=trim($_REQUEST['auditid']); 
       $year=trim($_REQUEST['year']); 
       $month=trim($_REQUEST['month']);   
       $status =$_REQUEST['status']; 
       $comment=$_REQUEST['comment']; 

       error_log($audit); 


      $con = mysql_connect("localhost","root","") or die("Sorry you are not connected to server. Try Again!"); 
      mysql_select_db("simauditdb", $con) or die ("Cannot connect to database."); 


      $insert= "insert into auditplan 
      values('','$audit','$year','$month','$status','$comment','1')"; 

      error_log($insert); 

       $result=mysql_query($insert) or die('Connection Failed'.mysql_error()); 
       echo "<script language='javascript'>alert('Audit Details Entered Successfully');</script>";  

       mysql_close($con); 

      } 
     elseif(isset($_POST['submit1'])) 
       { 
       echo "<script language='javascript'>document.location.href='Auditplan.php';</script>"; 
       }   
    ?> 

Answer 1

你沒有指定表單的動作和方法。 <form class="form-horizontal" role="form"> 試試這個

<form action="" method="post" lass="form-horizontal" role="form"> 

您發佈的價值觀，但你忘了指定的形式方法。