1
我有以下的數據集，我想通過end.station.id求和並變換成317行和72列矩陣間間隔
> sapply(df, class)
$end.station.id
[1] "integer"
$stoptime
[1] "POSIXct" "POSIXt"
$interval
[1] "POSIXct" "POSIXt"
> dim(df)
[1] 8256 3
> length(unique(df$end.station.id))
[1] 317
> length(unique(df$interval))
[1] 72
> head(df)
end.station.id stoptime interval
14785 437 2014-08-18 21:08:36 2014-08-18 21:00:00
16980 406 2014-08-18 20:34:22 2014-08-18 20:30:00
20200 372 2014-08-18 22:53:33 2014-08-18 22:50:00
20935 2000 2014-08-18 22:43:18 2014-08-18 22:40:00
22610 499 2014-08-18 20:51:28 2014-08-18 20:50:00
22678 401 2014-08-18 20:05:54 2014-08-18 20:00:00
我已經無法此使用dplyr
library(dplyr); library(tidyr); > matrix % + group_by(end.station.id, interval)%>% + summarise(sum = nrow) %>% + spread(end.station.id, nrow) Error: not a vector
我已經想分配唯一整數每個間隔的，但因爲它在POSIXct格式，數據是當我嘗試提取柱interval和順序將其與順序（X下降，= FALSE）丟失
最後，結果應該類似於這樣的矩陣，儘管填充了每個站點每間隔的總和。
> head(m)
station_id 2014-08-18 20:00:00 2014-08-18 20:10:00 2014-08-18 20:20:00
1 302 0 0 0
2 487 0 0 0
3 218 0 0 0
4 465 0 0 0
5 160 0 0 0
6 291 0 0 0
2014-08-18 20:30:00 2014-08-18 20:40:00 2014-08-18 20:50:00 2014-08-18 21:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-18 21:10:00 2014-08-18 21:20:00 2014-08-18 21:30:00 2014-08-18 21:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-18 21:50:00 2014-08-18 22:00:00 2014-08-18 22:10:00 2014-08-18 22:20:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-18 22:30:00 2014-08-18 22:40:00 2014-08-18 22:50:00 2014-08-18 23:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-18 23:10:00 2014-08-18 23:20:00 2014-08-18 23:30:00 2014-08-18 23:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-18 23:50:00 2014-08-19 00:00:00 2014-08-19 00:10:00 2014-08-19 00:20:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 00:30:00 2014-08-19 00:40:00 2014-08-19 00:50:00 2014-08-19 01:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 01:10:00 2014-08-19 01:20:00 2014-08-19 01:30:00 2014-08-19 01:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 01:50:00 2014-08-19 02:00:00 2014-08-19 02:10:00 2014-08-19 02:20:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 02:30:00 2014-08-19 02:40:00 2014-08-19 02:50:00 2014-08-19 03:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 03:10:00 2014-08-19 03:20:00 2014-08-19 03:30:00 2014-08-19 03:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 03:50:00 2014-08-19 04:00:00 2014-08-19 04:10:00 2014-08-19 04:20:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 04:30:00 2014-08-19 04:40:00 2014-08-19 04:50:00 2014-08-19 05:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 05:10:00 2014-08-19 05:20:00 2014-08-19 05:30:00 2014-08-19 05:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 05:50:00 2014-08-19 06:00:00 2014-08-19 06:10:00 2014-08-19 06:20:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 06:30:00 2014-08-19 06:40:00 2014-08-19 06:50:00 2014-08-19 07:00:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 07:10:00 2014-08-19 07:20:00 2014-08-19 07:30:00 2014-08-19 07:40:00
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
5 0 0 0 0
6 0 0 0 0
2014-08-19 07:50:00
1 0
2 0
3 0
4 0
5 0
6 0
，當我這樣做，我收到以下錯誤：'錯誤：值列「nrow」不input.' –
見更新存在剛纔下一行。 –
優秀，謝謝 –