組間隔時間間隔爲5秒

Question

我有包含秒[時間]值的數據。我想根據每秒多少條記錄來計數我的數據。

這是這樣的：

SELECT [Time], count(*) 

FROM [dbo].[Times] 
GROUP BY 
[Time] ORDER By [Time] 

這給了我：

+----------+----+ 
| 00:00:00 | 4 | 
+----------+----+ 
| 00:00:01 | 2 | 
+----------+----+ 
| 00:00:02 | 1 | 
+----------+----+ 
| 00:00:08 | 2 | 
+----------+----+ 
... 

我想組，並在5秒間隔數得過來，所以結果看起來像：

+----------+----+ 
| 00:00:05 | 7 | <-- # of records between 0:00:00 and 0:00:05 
+----------+----+ 
| 00:00:10 | 2 | <-- # of records between 0:00:05 and 0:00:10 
+----------+----+ 
... 

任何好的方法你在MS SQL中做到這一點？

Answer 1

這裏有一個方法：

select cast(dateadd(second, (datediff(second, 0, [time])/5) * 5, 0) as time(0)) as [time], 
     count(*) 
from [dbo].[Times] t 
group by dateadd(second, (datediff(second, 0, [time])/5) * 5, 0) 
order by min([time]); 

編輯：

正如評論指出的那樣，你可以這樣寫：

select v.[Time], count(*) 
from [dbo].[Times] t cross apply 
    (values (cast(dateadd(second, (datediff(second, 0, [time])/5) * 5, 0) as time(0))) 
    ) as v([Time]) 
group by v.[Time] 
order by v.[Time]; 

這使複雜的計算只在一個地方 - - 防止編輯原始答案時出現的錯誤類型。