的boost ::標記生成逗號分隔（C++）

Question

應該是一個容易爲你們.....

我與斷詞使用Boost玩弄，我想創建一個逗號分隔的令牌。這裏是我的代碼：

string s = "this is, , , a test"; 
boost::char_delimiters_separator<char> sep(","); 
boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep); 


for(boost::tokenizer<>::iterator beg= tok.begin(); beg!=tok.end(); ++beg) 
{ 
    cout << *beg << "\n"; 
} 

，我想輸出是：

This is 


a test 

我所得到的是：

This 
is 
, 
, 
, 
a 
test 

修訂

Answer 1

你必須給分離器標記生成器！

boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep); 

而且，與char_delimiter更換過時char_delimiters_separator：

string s = "this is, , , a test"; 
boost::char_separator<char> sep(","); 
boost::tokenizer< boost::char_separator<char> > tok(s, sep); 
for(boost::tokenizer< boost::char_separator<char> >::iterator beg = tok.begin(); beg != tok.end(); ++beg) 
{ 
    cout << *beg << "\n"; 
} 

請注意，也有一個模板參數不匹配：這是好習慣的typedef這樣的複雜類型：所以最終的版本可能是：

string s = "this is, , , a test"; 
boost::char_separator<char> sep(","); 
typedef boost::tokenizer< boost::char_separator<char> > t_tokenizer; 
t_tokenizer tok(s, sep); 
for (t_tokenizer::iterator beg = tok.begin(); beg != tok.end(); ++beg) 
{ 
    cout << *beg << "\n"; 
}