困惑termios.h常數

Question

test.c的...

#include <termios.h> 
#include <stdio.h> 

int main() { 
    printf("%x\n",B600); 
} 

在我的系統中，這版畫 「8」。

海合會-M test.c的顯示

/usr/include/stdc-predef.h /usr/include/termios.h \ 
/usr/include/features.h /usr/include/x86_64-linux-gnu/sys/cdefs.h \ 
/usr/include/x86_64-linux-gnu/bits/wordsize.h \ 
/usr/include/x86_64-linux-gnu/gnu/stubs.h \ 
/usr/include/x86_64-linux-gnu/gnu/stubs-64.h \ 
/usr/include/x86_64-linux-gnu/bits/types.h \ 
/usr/include/x86_64-linux-gnu/bits/typesizes.h \ 
/usr/include/x86_64-linux-gnu/bits/termios.h \ 
/usr/include/x86_64-linux-gnu/sys/ttydefaults.h /usr/include/stdio.h \ 
/usr/lib/gcc/x86_64-linux-gnu/4.9/include/stddef.h /usr/include/libio.h \ 
/usr/include/_G_config.h /usr/include/wchar.h \ 
/usr/lib/gcc/x86_64-linux-gnu/4.9/include/stdarg.h \ 
/usr/include/x86_64-linux-gnu/bits/stdio_lim.h \ 
/usr/include/x86_64-linux-gnu/bits/sys_errlist.h 

內/usr/include/x86_64-linux-gnu/bits/termios.h的：

#define B600 0000010 

另一頭都沒有B600的定義。 8的價值從哪裏來？

Answer 1

在C中，開頭的零的數字面被解釋爲一個八進制數，所以010裝置10在八進制，因此8.