PHP如果mysqli查詢語句

Question

我正在創建一個網站，顯示一組問題，但我的問題是檢查用戶是否回答了問題，如果他們有，顯示一個「應答」標籤。

但是，目前，即使答案不在提交表中，它也會顯示每個問題的「已回答」標籤。任何幫助，將不勝感激。

while($data = mysqli_fetch_row($result)){ 
    if($data[0] != null){ 
    echo(' 
    <div class="col-md-4 col-sm-5"> 
    <div class="panel panel-default text-center"> 
     <div class="panel-heading"> 
     <span class="fa-stack fa-5x"> 
      <i class="fa fa-circle fa-stack-2x text-default"></i> 
      <i class="fa fa-codepen fa-stack-1x fa-inverse"></i> 
     </span> 
     </div> 
     <div class="panel-body"> 
     '); 
     if($result4 = mysqli_query($mysqli,"SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'")){ 
      echo "Answered"; 
     } else{ 
      echo "Not Answered"; 
     } 

     echo (' 
     <h4>'.$data[6].' - <small><i>'.$data[8].' points</i></small></h4> 
     <p>'.$data[7].'</p> 
     <a href="question.php?id='.$data[0].'" class="btn btn-primary btn-block">View Question </a> 
     </div> 
    </div> 
    </div> 
    ');} else{ 
    echo "No More Questions"; 
    } 
} 

我知道我在這裏犯了一個基本或愚蠢的錯誤，所以任何幫助表示讚賞。

Answer 1

//Mysql query to find number of answers for particular question. 
$answercount = mysqli_query($mysqli, "SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'"); 
$answercount = mysqli_num_rows($answercount); 

//PHP code 
if($answercount>0){ 
    echo "Answered"; 
} else{ 
    echo "Not Answered"; 
} 

Answer 2

你忘記mysqli_query("")

if ($result4 = mysqli_query($con, "SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'")) { 
    echo "Answered"; 
} else { 
    echo "Not Answered"; 
}