2013-05-18 53 views

回答

1

ON子句中這種情況下,移動狀態下,

SELECT u.Id,u.FirstName,u.LastName,u.Email,SUM(a.Amount) Amount 
FROM users u LEFT JOIN amount a ON i.ID = a.ID 
     AND a.ExpenseDate >= '2013-05-12' 
GROUP BY u.Id 

,從表amount第一優化過濾器記錄之前,將上表user加入。

+0

偉大的工作。謝謝。實際上有什麼不同?你能否解釋一下 – spod

+0

[關於此鏈接的更多解釋...](http://stackoverflow.com/questions/15706112/why-and-when-a-left-join-with-condition-in-where-clause-是 - 不等效到的) –