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我有一個我的數據結構類的最終項目,我無法弄清楚如何去做。我需要實現基數排序,我理解大部分的概念。但到目前爲止,我在網上找到的所有實現都嚴格使用整數,並且需要將其與我創建的其他類型(稱爲Note)一起使用,它是一個帶ID參數的字符串。 這是我到目前爲止,但不幸的是它沒有通過任何JUnit測試。使用節點而不是整數在Java中使用基數進行排序
package edu.drew.note;
public class RadixSort implements SortInterface {
public static void Radix(Note[] note){
// Largest place for a 32-bit int is the 1 billion's place
for(int place=1; place <= 1000000000; place *= 10){
// Use counting sort at each digit's place
note = countingSort(note, place);
}
//return note;
}
private static Note[] countingSort(Note[] note, long place){ //Where the sorting actually happens
Note[] output = new Note[note.length]; //Creating a new note that would be our output.
int[] count = new int[10]; //Creating a counter
for(int i=0; i < note.length; i++){ //For loop that calculates
int digit = getDigit(note[i].getID(), place);
count[digit] += 1;
}
for(int i=1; i < count.length; i++){
count[i] += count[i-1];
}
for(int i = note.length-1; i >= 0; i--){
int digit = getDigit((note[i].getID()), place);
output[count[digit]-1] = note[i];
count[digit]--;
}
return output;
}
private static int getDigit(long value, long digitPlace){ //Takes value of Note[i] and i. Returns digit.
return (int) ((value/digitPlace) % 10);
}
public Note[] sort(Note[] s) { //
Radix(s);
return s;
}
//Main Method
public static void main(String[] args) {
// make an array of notes
Note q = new Note(" ", " ");
Note n = new Note("CSCI 230 Project Plan",
"Each person will number their top 5 choices.\n" +
"By next week, Dr. Hill will assign which piece\n" +
"everyone will work on.\n");
n.tag("CSCI 230");
n.tag("final project");
Note[] Note = {q,n};
//print out not id's
System.out.println(Note + " Worked");
//call radix
Radix(Note);
System.out.println(Note);
//print out note_id's
}
}