2017-03-25 14 views
0

我無法使插入符號正常工作。從已知的例子開始,http://machinelearningmastery.com/feature-selection-with-the-caret-r-package/中的示例完美無瑕。rfe.defau中的R錯誤:「在x和y中應該有相同數量的樣本」

正如我雖然替代我自己的數據集,它失敗:

> results <- rfe(x, y, sizes=c(1:5), rfeControl=control) 
Error in rfe.default(x, y, sizes = c(1:5), rfeControl = control) : 
    there should be the same number of samples in x and y 

據我所知,在X和Y樣品的行數是相同的;

> nrow(x) 
[1] 691231 
> nrow(y) 
[1] 691231 

詳見下文。

我看過類似的問題,如R rfe function "caret" Package error: there should be the same number of samples in x and yR trying to get caret/rfe to work。後者是相關的,但似乎沒有幫助。我試着將我的y以矢量像

> y <- as.vector(y) 

> y <- as.vector(as.list(y)) 

但錯誤依然存在。 當然,我做了一些愚蠢的事情,我只是看不到我犯錯的地方。任何幫助表示讚賞。

:-)

YARC

----------------------細節----------- ---

------腳本--------

library(feather) 
library(mlbench) 
library(caret) 

path <- "faultclass.feather" 
df <- read_feather(path) 

set.seed(7) 
control <- rfeControl(functions=rfFuncs, method="cv", number=10) 
x <- subset(df,select=-c(fault)) 
y <- df["fault"]*1 
results <- rfe(x, y, sizes=c(1:5), rfeControl=control) 
print(results) 
predictors(results) 
plot(results, type=c("g", "o")) 

------特點------

> str(x) 
Classes ‘tbl_df’, ‘tbl’ and 'data.frame': 691231 obs. of 31 variables: 
$ A    : chr "2011-12-06 00:00:00" "2011-03-11 00:00:00" "2014-11-17 00:00:00" "2013-01-07 15:19:02" ... 
$ B    : num 6 6 11 11 6 6 6 6 6 6 ... 
$ C    : num NA NA NA NA NA NA NA NA NA NA ... 
$ D    : chr "2016-01-01 00:00:00" "2016-01-01 00:00:00" "2016-01-01 00:00:00" "2016-01-01 00:00:00" ... 
$ E    : chr NA NA NA NA ... 
$ F    : num 0 230 230 230 230 230 230 230 230 0 ... 
$ G    : num 13 35 38 128 12 6 10 4 2 6 ... 
$ H    : chr NA NA NA NA ... 
$ J    : chr "35" "35" "28" "34" ... 
$ K    : num 0 63 32 63 40 40 35 40 35 25 ... 
$ L    : num 3 3 3 3 3 3 3 2 2 2 ... 
$ M    : num 301 301 301 301 301 301 301 301 301 301 ... 
$ N    : chr "613.0" "9630.0" "9114.0" "600.0" ... 
$ O    : chr "000356039" "000664676" "000770082" "000617804" ... 
$ P    : chr "11610000" "0000003001" "1161000" "43850" ... 
$ Q    : num 10089 10089 10972 27629 27630 ... 
$ R    : num 7.07e+17 7.07e+17 7.07e+17 7.07e+17 7.07e+17 ... 
$ S    : num 1 1 1 1 1 1 1 1 1 1 ... 
$ T    : chr "XX" "XX" "809" "96" ... 
$ U    : chr "cac" "edr" "ssr" "nsk" ... 
$ V    : chr "1954-05-17 00:00:00" "1973-05-17 00:00:00" "1997-06-24 00:00:00" "1976-12-24 00:00:00" ... 
$ W    : num 287 287 287 665 664 664 664 664 664 664 ... 
$ X    : num 1 1 1 1 1 1 1 1 1 1 ... 
$ Y    : num NA NA NA NA NA NA NA NA NA NA ... 
$ Z    : num 24828 39591 8932 35162 28540 ... 
$ AA    : chr "0001" "0001" "0001" "0002" ... 
$ AB    : chr "0001-TRA" "0001-TRB" "0001-TRC" "0002-TRD" ... 
$ AC    : chr "0,230" "0,230" "0,230" "0,230" ... 
$ AD    : chr "K03" "K03" "K03" "K05" ... 
$ AE    : num 3 3 3 3 3 3 3 3 3 3 ... 
$ AF    : chr "IT" "IT" "IT" "IT" ... 

> str(y) 
'data.frame': 691231 obs. of 1 variable: 
$ fault: num 0 0 0 0 0 0 0 0 0 0 ... 

回答

0

我有同樣的問題,最終我得到了它通過使用

y = as.vector(unlist(c(y))) 

工作,我不知道爲什麼這是不同的,以

y = as.vector(y) 

,但這對我來說是什麼工作。

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