如何將UITapGestureRecognizer添加到表格視圖單元格內的UILabel中？

Question

我正在使用NIB文件來佈置自定義表格視圖單元格。這個單元格帶有一個名爲lblName的標籤。將UITapGestureRecognizer添加到此標籤永遠不會觸發關聯的事件。我有userInteractionEnabled = YES。

我猜測問題是UILabel在TableView中，並且表格/單元格視圖正在攔截水龍頭。我能做些什麼嗎？

我想要做的就是在按下UILabel時執行一些自定義操作！我所見過的所有解決方案都很荒謬。使用標準工具集應該很容易。但顯然不是。

下面是我使用的代碼：

- (void)tapAction { 
    NSLog(@"Tap action"); 
} 

- (void)viewDidLoad 
{ 
    [super viewDidLoad]; 
    // Do any additional setup after loading the view from its nib 

    UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
    [recognizer setNumberOfTapsRequired:1]; 
    //lblName.userInteractionEnabled = true; (setting this in Interface Builder) 
    [lblName addGestureRecognizer:recognizer]; 
} 

Answer 1

EASY WAY創建的UILabel ：

您也可以使用隱形b utton在該標籤的頂部。所以它會減少您爲該標籤添加tapGesture的工作。

另一種方式：

你不應該爲UILabel創建一個IBOutlet。當你這樣做時，你會在自定義類實現文件中添加一個插座。您無法在其他文件中訪問。因此，在自定義類IB中爲該標籤設置標籤，並在cellForRowAtIndexPath:方法中編寫代碼。

更新：

在cellForRowAtIndexPath:方法，

for(UIView *view in cell.contentViews.subviews) { 
    if(view.tag == 1) { 
     UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
     [tap setNumberOfTapsRequired:1]; 
     [view addGestureRecognizer:tap]; 
    } 
} 

Answer 2

這樣做的工作沒有問題：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    ... 
    // create you cell 
    UILabel *lbl = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 100, 50)]; 
    [lbl setText:@"example"]; 
    [lbl setUserInteractionEnabled:YES]; 
    [cell.contentView addSubview:lbl]; 
    UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction:)]; 
    tap.tag = [NSIndexPath row]; 
    [tap setNumberOfTapsRequired:1]; 
    [lbl addGestureRecognizer:tap]; 
    ... 
} 

- (void)tapAction:(id)sender { 
    switch(((UITapGestureRecognizer *)sender).view.tag) { 
    case 0: 
      // code 
      break; 
    case 1: 
     // code 
     break; 
     .... 
    } 
} 

即使在情況下，與IB

Answer 3

方式的Dinesh建議的for循環使用屬性變量而不將工作。

UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
[tap setNumberOfTapsRequired:1]; 
[self.myUILabel addGestureRecognizer:tap]; 

Answer 4

UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
[recognizer setNumberOfTapsRequired:1]; 
lblName.userInteractionEnabled = YES; 
[lblName addGestureRecognizer:recognizer]; 

Answer 5

一旦指定點擊手勢到的UILabel和用戶交互設置爲啓用，在你的回調函數，你可以你可以添加在你的細胞的-awakeFromNib方法

UITapGestureRecognizer* gesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapGestureRecognizerAction:)]; 
[self.yourLabel setUserInteractionEnabled:YES]; 
[self.yourLabel addGestureRecognizer:gesture]; 

Answer 6

下一個從單元格視圖中查找索引路徑，但在超級視圖中搜索：

- (UITableViewCell *) findCellInSuperview:(UIView *)view 
{ 
UITableViewCell *cell = nil; 

    NSString *className = NSStringFromClass([[view superview] class]); 
    if ([className isEqualToString:@"UITableViewCell"]) { 
     cell = (UITableViewCell *)[view superview]; 
    } else { 
     if ([view superview] != nil) { 
      cell = [self findCellInSuperview:[view superview]]; 
     } 
    } 

return cell; 
} 

Answer 7

對於Swift ， 你可以在你的cellForRowAtIndexPath方法中添加這個。

var tap = UITapGestureRecognizer(target: self, action: "labelTapped") 
tap.numberOfTapsRequired = 1 
cell.label.addGestureRecognizer(tap) 
cell.label.tag = indexPath.row 

然後，對於動作

func labelTapped(gesture: UITapGestureRecognizer) { 
    let indexPath = NSIndexPath(forRow: gesture.view!.tag, inSection: 0) 
    let cell = tableView.cellForRowAtIndexPath(indexPath) as UITableViewCell 

    // Do whatever you want. 
} 

Answer 8

可以使用以下代碼來對UILable添加敲擊手勢中的UITableView細胞

UITapGestureRecognizer *lblAction = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(lblClick:)]; 
lblAction.delegate =self; 
lblAction.numberOfTapsRequired = 1; 
cell.lbl.userInteractionEnabled = YES; 
[cell.lbl addGestureRecognizer:lblAction]; 

和訪問選擇方法

- (void)lblClick:(UITapGestureRecognizer *)tapGesture { 
    UILabel *label = (UILabel *)tapGesture.view; 
    NSLog(@"Lable tag is ::%ld",(long)label.tag); 
} 

對於斯威夫特

let tapGesture : UITapGestureRecognizer = UITapGestureRecognizer.init(target: self, action: #selector(lblClick(tapGesture:))) 
tapGesture.delegate = self 
tapGesture.numberOfTapsRequired = 1 
cell.lbl.userInteractionEnabled = true 
cell.lbl.tag = indexPath.row 
cell.lbl.addGestureRecognizer(tapGesture) 

func lblClick(tapGesture:UITapGestureRecognizer){ 
    print("Lable tag is:\(tapGesture.view!.tag)") 
} 

Answer 9

對於斯威夫特3

let tapGesture : UITapGestureRecognizer = UITapGestureRecognizer.init(target: self, action: 
#selector(lblClick(tapGesture:))) 
tapGesture.delegate = self 
tapGesture.numberOfTapsRequired = 1 
cell.lbl.isUserInteractionEnabled = true 
cell.lbl.tag = indexPath.row 
cell.lbl.addGestureRecognizer(tapGesture) 

然後

func lblClick(tapGesture:UITapGestureRecognizer){ 
    print("Lable tag is:\(tapGesture.view!.tag)") 
}