內連接在Django 1.9

Question

我有這兩種模式：

class ModelInteractions(models.Model): 
    id1 = models.IntegerField(primary_key=True) 
    id2 = models.IntegerField() 
    comm = models.TextField(blank=True, null=True) 

    class Meta: 
     managed = False 
     unique_together = (('id1', 'id2'),) 


class Models(models.Model): 
    id = models.IntegerField(primary_key=True) 
    name = models.TextField() 

    class Meta: 
     managed = False 

，我想也comm選擇。在我看來，我用下面的代碼來Models獲取數據：

condition = Q(name__icontains=names[0]) 
for name in names[1:]: 
    condition &= Q(name__icontains=name) 
# ↓↓↓ this line is for what I need but it doesn't work 
condition &= Q(ModelInteractions__id2=id) 

models = Models.objects.filter(condition) 

id是在請求（def details(request, id):）接收。

我需要從ModelInteractions中選擇comm，其中id2 = id（根據請求收到ID）。

當前的代碼返回：

Cannot resolve keyword 'ModelInteractions' into field. Choices are: id, name 

Answer 1

class ModelInteractions(models.Model): 
    id1 = models.IntegerField(primary_key=True) 
    id2 = models.IntegerField() 
    comm = models.TextField(blank=True, null=True) 

    class Meta: 
     managed = False 
     unique_together = (('id1', 'id2'),) 


class Models(models.Model): 
    id = models.IntegerField(primary_key=True) 
    name = models.TextField() 
    interaction= models.ForeignKey(ModelInteractions,on_delete=models.CASCADE) 

讓你的模型是這樣，那麼makemigrations和遷移

然後運行相同的查詢到這裏

condition = Q(name__icontains=names[0]) 
for name in names[1:]: 
    condition &= Q(name__icontains=name) 

然後改變這一行

condition &= Q(interaction__id2=id) 

然後

models = Models.objects.filter(condition)