如何從JSONObject中檢索字符串數組？

-1

我JSONArray包含各種JSONObject S的這個樣子：如何從JSONObject中檢索字符串數組？

{"nearby":0,"x":0,"name":["OPS","BHU"],"y":0} 

{"nearby":0,"x":0,"name":["None"],"y":1} 

{"nearby":0,"x":0,"name":["None"],"y":2} 

{"nearby":0,"x":0,"name":["None"],"y":3} 

{"nearby":0,"x":0,"name":["None"],"y":4} 

{"nearby":0,"x":0,"name":["None"],"y":5} 

{"nearby":0,"x":0,"name":["None"],"y":6} 

{"nearby":0,"x":1,"name":["None"],"y":0} 

{"nearby":0,"x":1,"name":["None"],"y":1} 

{"nearby":0,"x":1,"name":["None"],"y":2} 

{"nearby":0,"x":1,"name":["DDF","THG"],"y":3} 

{"nearby":0,"x":1,"name":["None"],"y":4} 

{"nearby":0,"x":1,"name":["None"],"y":5} 

{"nearby":1,"x":1,"name":["ABC","DEF","XYZ"],"y":6}

我想在JSONObject，並從這樣一個數組來檢索對應於name鍵值：

JSONObject jo= jsonArray.getJSONObject(i); 
String nearby= jo.getString("nearby"); 
String xString= jo.getString("x"); 
int x=Integer.parseInt(xString); 
String yString= jo.getString("y"); 
int y=Integer.parseInt(yString); 
String[][] name=new String[7][7]; 
name[x][y]= ????????

使得輸出是像：

name[0][0]=["OPS","BHU"] 
name[0][1]=["None"] 
name[0][2]=["None"] 
name[0][3]=["None"] 
name[0][4]=["None"] 
name[0][5]=["None"] 
name[0][6]=["None"] 
name[1][0]=["None"] 
name[1][1]=["None"] 
name[1][2]=["None"] 
name[1][3]=["DDF","THG"] 
name[1][4]=["None"] 
name[1][5]=["None"] 
name[1][6]=["ABC","DEF","XYZ"]

來源

2017-04-25 A.Ro

請提供[MCVE] - 確保將其減少到最低限度* *，但完整的例子，以及格式。 –

我希望這是你在找什麼f或者，

var arr = [ 
 
    {"nearby":0,"x":0,"name":["OPS","BHU"],"y":0}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":1}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":2}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":3}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":4}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":5}, 
 
    {"nearby":0,"x":0,"name":["None"],"y":6}, 
 
    {"nearby":0,"x":1,"name":["None"],"y":0}, 
 
    {"nearby":0,"x":1,"name":["None"],"y":1}, 
 
    {"nearby":0,"x":1,"name":["None"],"y":2}, 
 
    {"nearby":0,"x":1,"name":["DDF","THG"],"y":3}, 
 
    {"nearby":0,"x":1,"name":["None"],"y":4}, 
 
    {"nearby":0,"x":1,"name":["None"],"y":5}, 
 
    {"nearby":1,"x":1,"name":["ABC","DEF","XYZ"],"y":6}, 
 
    ] 
 

 
    var resultArr = [[],[]]; 
 

 
    $.each(arr, function (key, item) { 
 
    resultArr[item.x][item.y]=item.name; 
 
    }); 
 

 
    console.log(resultArr[0][0]) 
 
    console.log(resultArr[0][1]) 
 
    console.log(resultArr[0][5]) 
 
    console.log(resultArr[1][4]) 
 
    console.log(resultArr[1][6])

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

來源

2017-04-25 09:16:06

如何從JSONObject中檢索字符串數組？

回答

相關問題