cURL to Python：使用請求時連接錯誤模塊

我想將使用cURL命令的bash代碼移動到Python 2.7腳本中。cURL to Python：使用請求時連接錯誤模塊

捲曲工作的命令是：

$ curl --data "vm_id='52e4130d-ffe0-495a-87c0-fc84200252ed'&gpu_ip='10.2.0.22'&gpu_port='8308'&mock_ip='10.254.254.254'&mock_port='8308'" http://rodvr-services:8080/rodvr-assign_gpu

我的Python腳本包含此：

import requests 
import requests.packages.urllib3 
requests.packages.urllib3.disable_warnings() 

payload = {'vm_id': '52e4130d-ffe0-495a-87c0-fc84200252ed', 'gpu_ip': '10.2.0.22', 'gpu_port': '8308', 'mock_ip': '10.254.254.254', 'mock_port': '8308'} 
r = requests.get('http://rodvr-services:8080/rodvr-assign_gpu', params=payload)

當我執行該腳本，我得到以下錯誤：

$ python exec.py 
Traceback (most recent call last): 
File "exec.py", line 9, in <module> 
    r = requests.post('http://rodvr-services:8080/rodvr-assign_gpu', params=payload) 
File "/usr/local/lib/python2.7/dist-packages/requests/api.py", line 112, in post 
    return request('post', url, data=data, json=json, **kwargs) 
File "/usr/local/lib/python2.7/dist-packages/requests/api.py", line 58, in request 
    return session.request(method=method, url=url, **kwargs) 
File "/usr/local/lib/python2.7/dist-packages/requests/sessions.py", line 502, in request 
    resp = self.send(prep, **send_kwargs) 
File "/usr/local/lib/python2.7/dist-packages/requests/sessions.py", line 612, in send 
    r = adapter.send(request, **kwargs) 
File "/usr/local/lib/python2.7/dist-packages/requests/adapters.py", line 490, in send 
    raise ConnectionError(err, request=request) requests.exceptions.ConnectionError: ('Connection aborted.', BadStatusLine('\n',))

以防萬一，我檢查了使用Python 3將會發生什麼，並且這是輸出：

HTTPConnectionPool(host='rodvr-services', port=8080): Max retries exceeded with url: /rodvr-assign_gpu?mock_ip=10.254.254.254&vm_id=52e4130d-ffe0-495a-87c0-fc84200252ed&gpu_ip=10.2.0.22&mock_port=8308&gpu_port=8308 (Caused by <class 'http.client.BadStatusLine'>:

然而，使用的urllib2庫，它的工作原理：

data = "vm_id='52e4130d-ffe0-495a-87c0-fc84200252ed'&gpu_ip='10.2.0.22'&gpu_port='8308'&mock_ip='10.254.254.254'&mock_port='8308'" 
r = urllib2.Request(url='http://rodvr-services:8080/rodvr-assign_gpu', data=data) 
f = urllib2.urlopen(r) 
print f.read()

來源

2017-10-04 siserte

所有查詢參數似乎都有引號。嘗試將它們添加爲''''value'''。 –

@KlausD。使用'payload = {'vm_id'：''52e4130d-ffe0-495a-87c0-fc84200252ed'「，'gpu_ip'：''10.2.0.22'」，'gpu_port'：''8308'「，'mock_ip'：」 '10 .254.254.254''，'mock_port'：''8308'「}'產生相同的輸出。 – siserte

你可以檢查服務器日誌嗎？ –

嘗試r = requests.post('http://rodvr-services:8080/rodvr-assign_gpu', data=payload)

來源

2017-10-04 10:53:19

同樣的錯誤。 – siserte

This網站可幫助您將curl命令轉換爲Python代碼。
你可以看到下面該網站建議代碼：

import requests 

data = [ 
    ('vm_id', '\'52e4130d-ffe0-495a-87c0-fc84200252ed\''), 
    ('gpu_ip', '\'10.2.0.22\''), 
    ('gpu_port', '\'8308\''), 
    ('mock_ip', '\'10.254.254.254\''), 
    ('mock_port', '\'8308\''), 
] 

requests.post('http://rodvr-services:8080/rodvr-assign_gpu', data=data) 
# it is slightly different from your code

由於我個人的問題，我的筆記本電腦，我不能測試你的代碼。希望這對你有用。

來源

2017-10-04 12:19:54

我測試了這個解決方案，我仍然有同樣的錯誤。 – siserte

cURL to Python：使用請求時連接錯誤模塊

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