顯示值不存在於另一個表

Question

我有這個tbl_religion與字段名creldesc

和TBL_MEMBER這些領域

，我有這個疑問算在TBL_MEMBER所有現存宗教和也算不算。男性和女性與宗教的所以我做了這個查詢：

SELECT m.creldesc as type, 
    COUNT(m.creldesc) as total, 
    SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male, 
    SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female 
    FROM tbl_member as m, tbl_barangay as b, tbl_household as h 
    WHERE m.chholdnumber = h.chholdnumber and h.cbrgycode=b.cbrgycode and b.cbrgyname = 'AGAO' 
      and m.crelationdesc !='Brgy. Captain' 
    GROUP BY m.creldesc 
    ORDER BY tot DESC; 

，並得到如下的輸出：

我想要實現的是也以0作爲顯示來自tbl_religion剩餘的宗教值。我做了一個左連接但出現錯誤。有人可以幫助我如何達到目的？

type   total male female 
Roman Catholic  7  4  3 
Baptist   3  1  2 
Islam    3  3  0 
Iglesia ni Cristo 1  1  0 
Free Methodist  1  1  0 
Ang Dating Daan 1  0  1 
Aglipay/Filipinsta 0  0  0 
All the Gospel  0  0  0 
Alpha Omega  0  0  0 
and so on............................. 

Answer 1

這裏就是我所做的：

 SELECT tbl_member.creldesc AS type, 
      COUNT(tbl_member.creldesc) AS total, 
      SUM(CASE WHEN tbl_member.cgender::text = 'Male'::text THEN 1 ELSE 0 END) AS male, 
      SUM(CASE WHEN tbl_member.cgender::text = 'Female'::text THEN 1 ELSE 0 END) AS female 
     FROM tbl_member 
     GROUP BY tbl_member.creldesc 

     UNION 

     SELECT b.creldesc AS type, 0 AS total, 0 AS male, 0 AS female 
     FROM tbl_religion b 
     WHERE NOT (b.creldesc::text IN 
      (SELECT DISTINCT tbl_member.creldesc FROM tbl_member)) 
     GROUP BY b.creldesc; 

，這裏是它的輸出：

這就是所有:)我使用了UNION而不是LEFT JOIN。

Answer 2

使用相同連接的所有表，這樣的做法：

SELECT m.creldesc as type, COUNT(m.creldesc) as tot, 
    SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male, 
    SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female 
FROM tbl_religion 
LEFT JOIN tbl_member as m 
ON tbl_religion.creldesc=m.creldesc 
LEFT JOIN tbl_household as h 
ON m.chholdnumber = h.chholdnumber 
LEFT JOIN tbl_barangay as b 
ON h.cbrgycode=b.cbrgycode 
WHERE b.cbrgyname = 'AGAO' AND m.crelationdesc !='Brgy. Captain' 
GROUP BY m.creldesc 
ORDER BY tot DESC 

的... FROM tbl_member, tbl_barangay, tbl_household LEFT JOIN tbl_religion ...您當前的查詢方法是錯誤的，會產生語法錯誤。

Answer 3

你不能讓這樣的：

來自@表1，@ TABLE2，@表3
LEFT JOIN @ TABLE0 ON ...

只能從一個表中一次選擇的項目......相同加入。

SELECT m.creldesc as type, 
COUNT(m.creldesc) as tot, 
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male, 
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female 
FROM tbl_member as m 

LEFT JOIN tbl_religion z ON z.creldesc = m.creldesc 
LEFT JOIN tbl_barangay h ON h.cbrgycode=b.cbrgycode 

SO ON.... WITH JOINS 
    GROUP BY m.creldesc 

UPDATE WOKING CODE：

SELECT m.creldesc as type, COUNT(m.creldesc) as tot, SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male, 
    SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female 

FROM tbl_member as m 
    LEFT JOIN tbl_religion r ON r.creldesc = m.creldesc 
    LEFT JOIN tbl_barangay as b ON m.chholdnumber = b.cbrgycode 
    LEFT JOIN tbl_household as h ON h.cbrgycode = b.cbrgycode 

WHERE b.cbrgyname = 'AGAO' and m.crelationdesc !='Brgy. Captain' 
GROUP BY m.creldesc 
ORDER BY tot DESC