SQL：獲取所有客戶的最新付款？

Question

即時通訊使用Mysql 5.1，並給予與列customerid付款，paymentdate我需要所有客戶的最新付款。 所以用項目的表

row, customerid, paymentdate 
1 5   2011-03-01 
2 5   2011-04-01 
3 6   2011-01-01 
4 7   2011-01-01 
5 7   2011-02-01 

應該返回行2,3,5 查詢

select max(paymentdate),customerid from payments where customerid=5; 

，我試圖進入某種作品WHERE客戶IN（...），但沒有運氣，因爲它返回2列，不僅1

感謝

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最終的答案啓發我去尋找相關的信息，並與 解決了這個問題下面的查詢（如在文章中評論）

select * from (select * from payments order by paymentdate desc) as p group by customerid; 

same problem from mysql forum solutions from a related mysql article

Answer 1

你應該group by在客戶。

select max(paymentdate),customerid from payments group by customerid; 

Answer 2

另一種方法：

Select paymentdate,customerid from payments group by customerid order by paymentdate DESC; 

甚至：

Select distinct(customerid),paymentdate from payments order by paymentdate DESC; 

添加DESC的原因首先要返回最近的日期排序。