1
我已經在JQXgrid中創建了按鈕渲染器,當按鈕被點擊時,它將數據傳遞到控制器,並且控制器發送到模型,然後從mysql的數據返回結果。如何使用一個id傳遞多個值到模態
這是我的視圖代碼部分按鈕渲染:
var button_renderer = function (row, columnfield, value, defaulthtml, columnproperties) {
var kode_keramik = $('#jqxgrid').jqxGrid('getcelltext', row, "kode_keramik");
button = '<a href="#modal_details" class="btn btn-xs btn-success view_details" id="'+ kode_keramik +'" >Proceed</a>';
return button;
};
這是將數據傳遞到控制器我的視圖代碼部分:
$(document).on('click', ".view_details", function() {
//alert("aaa");
var url = "<?php echo base_url().'getGlazeMM/ajax_get_item_list'?>";
kode_keramik = this.id;
$.post(url, {kode_keramik: kode_keramik} ,function(data) {
$('.modal-body').empty();
$('.modal-body').append(data);
$('#modal_details').modal();
});
});
這是我的控制器:
public function ajax_get_item_list(){
$data['post'] = $_POST;
$kode_keramik = $_POST['kode_keramik'];
//$buyer = $_POST['buyer'];
$this->load->model('get_glaze');
$data['item_list'] = $this->get_glaze->action_ajax_get_item_list($data['post']);
if ($data['item_list']){
echo "<table class='table table-bordered'>
<tr>
<th>Inspect Date</th>
<th>Item Code</th>
<th>Type</th>
<th>Hasil KW1</th>
<th>Total Inspek</th>
<th>Aktual Yield</th>
<th>Buyer</th>
</tr>";
foreach ($data['item_list'] as $key => $value) {
echo "<tr>";
echo "<td>".$value['inspect_date']."</td>";
echo "<td>".$value['item_code']."</td>";
echo "<td>".$value['sell_type']."</td>";
echo "<td>".$value['hasil_kw1']."</td>";
echo "<td>".$value['total_inspek']."</td>";
echo "<td>".$value['aktual_yield']." %</td>";
echo "<td>".$kode_keramik."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "Data tidak ditemukan";
}
}
最大的問題是如何從view_details" id="'+ kode_keramik +'"
+ 第二個值上
var button_renderer = function (row, columnfield, value, defaulthtml, columnproperties) {
var kode_keramik = $('#jqxgrid').jqxGrid('getcelltext', row, "kode_keramik");
button = '<a href="#modal_details" class="btn btn-xs btn-success view_details" id="'+ kode_keramik +'" >Proceed</a>';
return button;
};
到:
var url = "<?php echo base_url().'getGlazeMM/ajax_get_item_list'?>";
kode_keramik = this.id;
***SECOND VALUE;***
$.post(url, {kode_keramik: kode_keramik, ***SECOND VALUE***} ,function(data) {
直到控制器:
public function ajax_get_item_list(){
$data['post'] = $_POST;
$kode_keramik = $_POST['kode_keramik'];
$***SECOND VALUE*** = $_POST['***SECOND VALUE***'];
親愛的Abanob,你的建議真棒,感謝兄弟... – user1909323