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感謝您的閱讀。我正在編寫一個腳本,以這種格式讀取生日:月/日/年,並將年,日,月分開。我得到了年份,但是對於那一天,我試圖用string.subtr(,)減去第二個'/'的位置值和最終位置值。所以,例如,我試圖在findDay()函數中從01/26/1994獲得01/26。 但是我似乎得到了第55行的「字符串沒有成員名爲'subtr'」的錯誤。有人可以引導我,因爲我是一個全新的程序員。此外,感謝您繼續提供幫助,因爲在收到本網站的輸入信息後,我的知識翻了一番。字符串沒有名爲'subtr'的成員錯誤
#include <iostream>
#include <cstdlib>
#include <string>
#include <fstream>
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
using namespace std;
void findYear(string &);
void findDay (string &);
void findMonth(string &);
int main()
{
string birthday;
cout << "Enter birthday: " << endl; // 01/26/1994
cin >> birthday;
string year = birthday;
string day = birthday;
string month = birthday;
findYear(year);
cout << year << endl;
findDay(day);
cout << day << endl;
system("pause");
return 0;
int slashpos = birthday.find('/');
}
void findYear(string &year)
{
int slashpos = year.find('/');
int i = 0;
string temp2;
while(year.at(year.length()-1-i)!='/')
{
temp2 += year.at(year.length()-1-i);
i++;
}
string rtemp2 = "";
for(int k = 0; k < temp2.length(); k++)
{
rtemp2 += temp2.at(temp2.length()-1-k);
year = rtemp2;
}
}
void findDay (string &day)
{
string tempday1 = "";
string temp2 = "";
int i = 0;
tempday1 = day.subtr(day.rfind('/'),day.length()-1); /* error here! [Error] 'std::string' has no member named 'subtr'*/
while(tempday1.at(tempday1.length()-1-i)!='/')
{
temp2 += tempday1.at(tempday1.length()-1-i);
i++;
}
string rtemp2 = "";
for(int k = 0; k < tempday1.length(); k++)
{
rtemp2 += tempday1.at(tempday1.length()-1-k);
day = rtemp2;
}
}
你需要'std :: string :: substr'。 – juanchopanza