從SQL結果彙總結果

Question

我想彙總一些結果，但我沒有任何運氣。下面是我使用的SQL與實際輸出：它生產這個數據

SQL語句：

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd, mtl_system_items_b i 
WHERE oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
    AND i.organization_id = :p_organization_id 
    AND oqd.organization_id = i.organization_id 
GROUP BY i.inventory_item_id, i.organization_id, primary_transaction_quantity 


INVENTORY_ITEM_ID,ORGANIZATION_ID,ON_HAND_QTY 
117567,7651,2 
117567,7651,1 

我需要什麼返回：

INVENTORY_ITEM_ID,ORGANIZATION_ID,ON_HAND_QTY 
117567,7651,3 

基本上，它需要總結的on_hand_qty並且只返回一個結果行，如果inventory_item_id和organization_id是相同的。任何幫助是極大的讚賞！從組

Answer 1

刪除primary_transaction_quantity by子句

Answer 2

好了，讓你有主要的問題是，你在你的GROUP BY所以您的查詢應該是這樣的包含您的累計聲明。

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd, mtl_system_items_b i 
WHERE oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
    AND i.organization_id = :p_organization_id 
    AND oqd.organization_id = i.organization_id 
GROUP BY i.inventory_item_id, i.organization_id 

不知道，如果你通過對谷歌你應該找到很多解釋它是如何工作的查找組您所使用但什麼DBMS。

現在讓我們繼續下一個問題。您正在使用pre ansi-92連接語法。這是bad。

你的代碼應該看起來像這樣。

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd 
INNER JOIN mtl_system_items_b i 
    ON oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.organization_id = i.organization_id 
    AND i.organization_id = :p_organization_id --Added back the function now that I know it isn't a typo 
WHERE 
    oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
GROUP BY i.inventory_item_id, i.organization_id