爲什麼我的java程序跳過我的輸入並掛在IF語句上？

Question

我的程序中的其他一切工作除了這個單一的方法，它跳過sc.next（），然後掛在我的if。

public static String getChoice() { 
    boolean choiceSelector = false; 

    // construct a Scanner object for getting input 
    Scanner sc = new Scanner(System.in); 

    System.out.println("Do you wish to continue? Y/N"); 
    String choice = " "; 

    do{ 
    choice = sc.next(); 

    if(choice.equalsIgnoreCase("Y")){ 
     choice="Y"; 
     choiceSelector = true; 
    } 
    if(choice.equalsIgnoreCase("N")){ 
     choice="N"; 
     choiceSelector = true; 
    } else 
     choice = sc.next("Please enter a correct value."); 

    } while(choiceSelector == false); 

    return choice; 
}//end getChoice 

Answer 1

可能把另一個else，因爲反正你問他們一個適當的值，即使輸入是Y起初還有：

if(choice.equalsIgnoreCase("Y")){ 
    choice="Y"; 
    choiceSelector = true; 
} else if(choice.equalsIgnoreCase("N"))... 

---

，並打破

choice = sc.next("Please enter a correct value."); // not a valid pattern provided as an input here 

as

System.out.println("Please enter a correct value."); 
choice = sc.next(); 

---

和

return choiceSelector; // the boolean value