從哈希

Question

刪除空值我有要求recive這樣PARAMS

params[:search] = {"user_id_in"=>[""], "status_in"=>[""], "priority_in"=>["", "8"]} 

我需要清除它，因爲元搜索寶石作品不正確使用它

params[:search] = {"priority_in"=>["8"]} 

Answer 1

我有雙重選擇功能的解決方案：

 
params[:search] = {"user_id_in"=>[""], "status_in"=>[""], "priority_in"=>["", "8"]} 

params[:search].select! do |k, v| 
    v.select! do |vv| 
    !vv.empty? 
    end 
    v.length > 0 
end 

Answer 2

功能性方法（除了當然，除非您要求進行就地更新，最後一次分配除外）：

pairs = params[:search].map { |k, vs| [k, vs.reject(&:blank?)] } 
params[:search] = Hash[pairs.select { |k, vs| vs.present? }]