CakePHP的3：多級聯想

Question

我有3個表，categories，products和seller_products及其關聯就像 CategoriesTable.php

$this->hasMany('Products', [ 
    'foreignKey' => 'category_id' 
]); 

ProductsTable.php

$this->hasMany('SellerProducts', [ 
    'foreignKey' => 'product_id' 
]); 

$this->belongsTo('Categories', [ 
    'foreignKey' => 'category_id', 
    'joinType' => 'INNER' 
]); 

SellerProductsTable.php

$this->belongsTo('Products', [ 
    'foreignKey' => 'product_id', 
    'joinType' => 'INNER' 
]); 

現在，在categories的view（site.com/categories/view/2），我不得不從products和sellerProducts選擇所有產品數據，其中產品所屬類別ID，也存在於sellerProducts。 即，

products.category_id = $id AND sellerProducts.product_id = Products.id 

有CakePHP中3任何簡單的方法來獲得結果呢？

編輯2

這就是我正在努力。在CategoriesController.php

$this->loadModel('Products'); 
     $sellerProducts = $this->Products->find('all', [ 
      'conditions' => [ 
      'category_id' => $id 
      ], 
      'joins' => [ 
       'table' => 'SellerProducts', 
       'alias' => 'SellerProducts', 
       'type' => 'INNER', 
       'conditions' => [ 
       'SellerProducts.product_id' => 'Products.id', 
       'stock >' => 0 
       ] 
      ] 
     ]); 
     debug($sellerProducts); 
     foreach($sellerProducts as $a) { 
      debug($a); 
     } 

上debugview()行動也只給出從Products表，但沒有從SellerProducts

Answer 1

，而不是加入你們可以只包含SellerProducts

$this->Products->find() 
    ->where(['category_id' => $id]) 
    ->contain(['SellerProducts' => function($q) { 
     return $q->where(['stock >' => 0]) 
    }]); 

，如果你想查詢數據您可以做的賣家產品的數據

$this->Products->SellerProducts->find() 
    ->where([ 
     'Products.category_id' => $id 
     'SellerProducts.stock >' => 0]) 
    ->contain(['Products', 'Products.Categories']);