GET週數和天從日期

Question

輸入：17-07-2017
輸出 - 提前
這裏>>第三個星期一

感謝是我的代碼：

$datee = "2017-07-17"; 
$timestamp = strtotime($datee); 
$day = date('l', $timestamp); 
$week = date('w', $timestamp); 
echo $day; 
echo $week; 

Answer 1

$input = new \DateTime('2017-07-17'); 
$firstDayOfMonth = new \DateTime($input->format('Y-m-01')); 
$order = (int)(($input->format('j') - 1)/7) + 1; 

function ordinal($number) { 
    $ends = array('th','st','nd','rd','th','th','th','th','th','th'); 
    if ((($number % 100) >= 11) && (($number%100) <= 13)) 
     return $number. 'th'; 
    else 
     return $number. $ends[$number % 10]; 
} 

echo ordinal($order).' '.$input->format('l'); 

您可以用代碼在鼓搗https://3v4l.org/dg5Xa

Answer 2

'W' 格式是一天的數字表示（星期日爲0，星期六爲6）。它不代表本月的周。爲了得到這個月的一週，你可以使用下面的函數

function week_number($date = 'today') { 
     return ceil(date('j', strtotime($date))/7); 
    } 

所以，你的代碼應該是：

$datee = "2017-07-17"; 
    $timestamp = strtotime($datee); 
    $day = date('l', $timestamp); 
    $week = week_number($datee); 
    echo $day; 
    echo $week; 

參考：Get week number in month from date in PHP?

Answer 3

很簡單的答案已經存在了

In PHP, how to know how many mondays have passed in this month uptil today?

$now=time(); 
if (($dow = date('w', $now)) == 0) $dow = 7; 
$begin = $now - (86400 * ($dow-1)); 

echo "Monday: ".ceil(date('d', $begin)/7)."<br/>";