Mysqli和期望2參數，1給出

Question

我得到mysqli錯誤，它期望2個參數，只有1，但我不能看到我失蹤。

  // Create connection 
      $con=mysqli_connect("connection stuff"); 

      // Check connection 
      if (mysqli_connect_errno()) { 
      echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
      } 

        <?php 
         if(isset($_POST['submit1011'])) 
         { 
         $query1 =mysqli_query ($con, "UPDATE blog_semicategory SET english_navn_godkend=".$_POST['godkend_english101']." WHERE semikatagori_id=" . $id) or die(mysqli_error()); 
         mysqli_query($query1); 
         echo('<META HTTP-EQUIV="refresh" CONTENT="1">'); 
         echo "<h3>Oprettes...</h3>"; 
         } 
        ?> 


         <center><img src="../include/images/<?php echo $r1011->english_navn_godkend ?>.png"></center><br /> 

         <center> 
          <form action="" method="post"> 
          <input type="hidden" name="godkend_english101" value="2"> 
          <input type="submit" name="submit1011" value="Godkend Navn" /> 
          </form> 
         </center> 

Answer 1

$query1 =mysqli_query ($con, "UPDATE blog_semicategory SET english_navn_godkend=".$_POST['godkend_english101']." WHERE semikatagori_id=" . $id) or die(mysqli_error()); 
mysqli_query($query1); 

$query1不是查詢。請參閱mysqli_query的手冊。該函數返回mysqli_result。實際上，您試圖執行相同的查詢兩次，第二次嘗試未指定第一個鏈接參數。