2017-04-02 58 views
-11
$result=mysqli_query($connection,$query); 
if(mysqli_affected_rows($connection)==1) 
+1

查看有多少相似項目在相關部分 –

回答

0

您的$連接參數以字符串形式給出,而它應該是mysqli對象。從php docs

$link = mysqli_connect("localhost", "my_user", "my_password", "world"); 

/* check connection */ 
if (mysqli_connect_errno()) { 
    printf("Connect failed: %s\n", mysqli_connect_error()); 
    exit(); 
} 

/* Create table doesn't return a resultset */ 
if (mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City") === TRUE) { 
    printf("Table myCity successfully created.\n"); 
} 
相關問題