計算列的每個值的百分比sql

我想重寫這個SQL查詢，以便他顯示一個記錄，如果沒有匹配，並且我希望他計算每個成員值的百分比而不是現在的'0'，任何人都可以幫我實現這個目標嗎？計算列的每個值的百分比sql

SELECT COUNT(Name) * 100/
    (select COUNT(*) from 'cities' 
    WHERE city= 'Hoeselt' AND Member = '0') AS 'perc', 
    CASE 
     WHEN age <= 30 THEN '18-30' 
     WHEN age <= 50 THEN '31-50' 
     ELSE '50+' 
    END AS age, COUNT(*) AS n 
FROM 'cities' 
    WHERE city= 'Hoeselt' AND elected='yes' AND Member= '0' 
    GROUP BY CASE 
     WHEN age <= 30 THEN '18-30' 
     WHEN age <= 50 THEN '31-50' 
     ELSE '50+' 
    END

來源

2013-01-03 user735646

很難確定這是否適用於沒有DDL的人。這是幫助人們爲您提供最佳解決方案的絕佳工具。 http://sqlfiddle.com/#!6

;WITH AgeCat AS 
(
    SELECT MinAge = 18 
      ,MaxAge = 30 
      ,Descr = '18-30' UNION ALL 
    SELECT 31, 49, '31-49'  UNION ALL 
    SELECT 50, 200, '50+' 
) 
SELECT DISTINCT 
     C.Descr 
     ,Perc = COUNT(*) OVER (PARTITION BY 0)/COUNT(*) OVER (PARTITION BY A.Descr) * 100 
FROM AgeCat A 
JOIN Cities C ON C.Age BETWEEN A.MinAge AND A.MaxAge 
WHERE city = 'Hoeselt' 
AND elected = 'yes' 
AND Member = '0'

來源

2013-01-03 13:43:27 MarkD

THX，將嘗試;） – user735646

COUNT（*）OVER（PARTITION BY 0）/ COUNT（*）OVER（PARTITION BY A.Descr） * 100改爲COUNT（*）OVER（PARTITION BY 0）/ COUNT（*）OVER（PARTITION BY C.Descr）* 100.對不起。再試一次 – MarkD

我認爲你可以使用'OVER（）'而不是'OVER（PARTITION BY 0）' –

我這個方法是使用一個CTE來定義的年齡組。接下來選擇所有年齡段作爲「駕駛員」表，留下加入城市信息。然後，你甚至年齡組時沒有匹配：

with c as (
    select c.*, 
      (CASE WHEN age <= 30 THEN '18-30' 
       WHEN age <= 50 THEN '31-50' 
       ELSE '50+' 
      END) as agegrp 
    from cities 
    ) 
select COUNT(Name) * 100/(select COUNT(*) from cities WHERE city= 'Hoeselt' AND Member = '0') as perc, 
     driver.agegrp, 
     COUNT(*) as n 
from (select distinct agegrp from c) as driver left outer join 
    c 
    on driver.agegrp = c.agegrp 
group by driver.agegrp

來源

2013-01-03 14:13:41

計算列的每個值的百分比sql

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