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我試圖構建一個創建密碼的gui,並且儘可能地生成密碼並使其顯示在標籤中。然而,當多次點擊按鈕時,舊密碼看起來並不會消失,只是重疊在頂部。我也遇到了一個我似乎無法糾正的錯誤,儘管它似乎不影響gui。Python Tkinter標籤刷新
到目前爲止的代碼是:
from tkinter import *
import random
myGui = Tk()
myGui.geometry('300x200+700+250')
myGui.title('Password Generator')
def passwordgen():
password = ''
for i in range(8):
##----runs the for loop 8 times
if (i == 0) or (i == 4):
password = password + chr(random.randint(97, 122))
if (i == 1) or (i == 5):
password = password + chr(random.randint(65, 90))
if (i == 2) or (i == 6):
password = password + chr(random.randint(48, 57))
if (i == 3) or (i == 7):
password = password + chr(random.randint(33, 47))
passLabel = Label(myGui, text=password)
passLabel.grid(row=0, column=1, sticky=E)
genPassBtn = Button(myGui, text="Generate Password", command=passwordgen)
genPassBtn.bind("<Button-1>", passwordgen)
genPassBtn.grid(row=0, column=0, sticky=W)
myGui.mainloop()
我收到的錯誤是:
return self.func(*args)
TypeError: passwordgen() takes 0 positional arguments but 1 was given
我希望達到的結果是創建生成密碼的GUI,生成一個散列生成密碼的值,檢查密碼強度,將生成的散列加載到文本文件,然後可以根據存儲的散列驗證密碼。
此外,從收到的建議,我修改了代碼,並增加了額外的檢查力量。現在,該代碼如下所示:
from tkinter import *
import random
myGui = Tk()
myGui.geometry('300x200+700+250')
myGui.title('Password Generator')
def passwordgen():
password = ''
for i in range(8):
##----runs the for loop 8 times
if (i == 0) or (i == 4):
password = password + chr(random.randint(97, 122))
if (i == 1) or (i == 5):
password = password + chr(random.randint(65, 90))
if (i == 2) or (i == 6):
password = password + chr(random.randint(48, 57))
if (i == 3) or (i == 7):
password = password + chr(random.randint(33, 47))
strPassword.set(password)
def checkPassword():
strength = ['Blank', 'Very Weak', 'Weak', 'Medium', 'Strong', 'Very Strong']
score = 1
password = strPassword.get()
if len(password) < 1:
return strength[0]
if len(password) < 4:
return strength[1]
if len(password) >= 8:
score += 1
if re.search('[0-9]', password):
score += 1
if re.search('[a-z]', password) and re.search('[A-Z]', password):
score += 1
if re.search('.', password):
score += 1
passwordStrength.set(strength[score])
genPassBtn = Button(myGui, text="Generate Password", command=passwordgen)
strPassword = StringVar()
lblPassword = Label(myGui, textvariable=strPassword)
lblPassword.grid(row=0, column=1, sticky=W)
genPassBtn.grid(row=0, column=0, sticky=W)
passwordStrength = StringVar()
checkStrBtn = Button(myGui, text="Check Strength", command=checkPassword)
checkStrBtn.grid(row=1, column=0)
checkStrLab = Label(myGui, textvariable=passwordStrength)
checkStrLab.grid(row=1, column=1)
myGui.mainloop()
非常感謝斯科蒂。我現在可以使用strPassword並檢查強度嗎? – JSmith
我不確定你的意思是什麼,但你可以使用strPassword.get()返回字符串的內容以用於其他目的 – scotty3785
我想說這個密碼非常弱,弱,中,強等。 aginst一組參數,如小寫,大寫,數字或特殊字符。 – JSmith