刷新Tkinter表

Question

我正在開展一個高峯時段的遊戲。我正在構建一個GUI來顯示我找到的解決方案。 我建立了一個保存當前狀態的表。現在我想更新板到下一個狀態。我如何刷新GUI？

import Tkinter as tk 
dict = {'X':'red', 'A': 'cyan', 'B': 'dark green', 'C': 'gold', 'D': 'green2', 'E': 'tan1', 'F': 'deep pink', 'G': 'bisque2', 'H': 'navy', 'I': 'orange', 'J': 'khaki1', 'K': 'purple1', 'O': 'Lightblue3', 'P': 'salmon', 'Q': 'lemon chiffon', 'R': 'OliveDrab2'}; 
class ExampleApp(tk.Tk): 
    def __init__(self, board): 
     tk.Tk.__init__(self) 
     t = SimpleTable(self, board, 8, 8) 
     t.pack(side="top", fill="x") 
     t.set(7,7,"2") 

class SimpleTable(tk.Frame): 
    def __init__(self, parent, board, rows=8, columns=8): 
     # use black background so it "peeks through" to 
     # form grid lines 
     tk.Frame.__init__(self, parent, background="black") 
     self._widgets = [] 
     for i in range(rows): 
      current_row = [] 
      for j in range(columns):  
       if (i >= 1 and i <=6 and j >= 1 and j <=6): 
        vehicleId = board[i-1][j-1] 
        if (vehicleId != ' '):    
         label = tk.Label(self, text=vehicleId, bg=dict[vehicleId], borderwidth=0, width=10) 
        else: 
         label = tk.Label(self, text=vehicleId, bg='gray75', borderwidth=0, width=10)      
       elif (i == 3 and j == 7): 
        label = tk.Label(self, text="exit", bg='gray30', borderwidth=0, width=10) 
       else: 
        label = tk.Label(self, text="", bg='gray60', 
           borderwidth=0, width=10) 
       label.grid(row=i, column=j, sticky="nsew", padx=2, pady=2) 
       current_row.append(label) 
      self._widgets.append(current_row) 
     for j in range(columns): 
      self.grid_columnconfigure(j, weight=1) 

    def set(self, row, column, value): 
     widget = self._widgets[row][column] 
     widget.configure(text=value) 

if __name__ == "__main__": 
    # initial state 
    board = [['O', ' ', ' ', ' ', ' ', ' '], ['O', ' ', ' ', ' ', ' ', ' '],  ['O', 'X', 'X',' ', ' ', ' '], ['P', ' ', 'A', 'Q', 'Q', 'Q'], ['P', ' ', 'A', ' ', ' ', 'B'],['P', ' ', 'R', 'R', 'R', 'B']] 
    # second state 
    board2 = [['O', ' ', ' ', ' ', ' ', ' '], ['O', ' ', ' ', ' ', ' ', ' '], ['O', ' ', 'X','X', ' ', ' '], ['P', ' ', 'A', 'Q', 'Q', 'Q'], ['P', ' ', 'A', ' ', ' ', 'B'],['P', ' ', 'R', 'R', 'R', 'B']] 
    app = ExampleApp(board) 
    app.mainloop() 

Answer 1

您必須保留對小部件的引用，您可以稍後使用它來更改文本。例如，你可以保持標籤的列表，每一行：

labels = [] 
for i in range(rows): 
    labels.append([]) 
    for j in range(columns): 
     ... 
     label = Label(...) 
     labels[-1].append(label) 
... 

修改文本，使用標籤的config方法：

for i in range(rows): 
    for j in range(columns): 
     labels[i][j].config(text="this is new text")