隨機數發生器自動隨機

Question

我們知道下面的代碼是隨機數

Random generator = new Random(); 
number = generator.nextInt(VALUE) + 1; 

我可以把這個代碼隨機生成，如果點擊該按鈕

button1 = (Button)findViewById(R.id.buttonblack); 
if(v==button1) { 

// Here, we are generating a random number 
Random generator = new Random(); 
number = generator.nextInt(5) + 1; 
// The '5' is the number of values 

// Here, we are checking to see what the output of the random was 
switch(number) { 

    case 1: if(bla.. bla.. bla.. == 1){ 
      //Do some blaa. blaa. blaa. logic 
     } 
     else if(bla.. bla.. bla.. == 2){ 
      //Do some blaa. blaa. blaa. logic 
     } 
     break; 
     //and so on.. 

我的問題是如何使隨機生成方法自動爲隨機每隔2秒，然後速度越來越快，而不是通過點擊按鈕

以及如何，如果一些按鈕點擊隨機停止，例如

buttonstop = (Button)findViewById(R.id.buttonstop);  
buttonstop.setOnClickListener(new View.OnClickListener() { 

     public void onClick(View v){ 

      //Stop Random generator 

     } 
    }); 

任何人都可以回答？感謝的

Answer 1

使用它從2秒後開始以更快的20毫秒

private Handler mHandler = new Handler(); 
    int ms=2000; //2secs. 
    Define a Runnable: 

    private Runnable mUpdateTimeTask = new Runnable() { 
     public void run() { 
      // get random number here 

     // You could do this call if you wanted it to be periodic: 

    ms=ms-20; //20ms faster 
      mHandler.postDelayed(this, ms); 

      } 
     }; 

    mHandler.postDelayed(mUpdateTimeTask, 100);